They are circle and triangle.
Best of luck in geometry
Answer:
Whats your question?
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
Let number of m&ms Garry has be g
number of m&ms Larry has be l
Number of m&ms Jerry has be j
Since Gary has TWICE as Larry, we can write:
g = 2l
Also, Jerry has THRICE as Larry, we can write:
j = 3l
Together, they have 108, thus, we can write:
g + l + j = 108
Putting 1st and 2nd equation in 3rd, we can solve for Larry first. Shown below:

Larry has 18. To find Gary's number, we can use the fact g = 2l, so
g = 2 * 18 = 36
Gary has 36 m&ms
Answer:
1. A. 12a^2 + 8a + 4
2. C. 4xy+16x-4y^2-16y
3. C. 64q^6r^8s^4
4. A. -4x^4y^6
Step-by-step explanation:
48a^3 + 32a^2 + 16a / 4a = (48a^3) / 4a + (32a^2) / 4a + (16a) / 4a = 12a^2 + 8a + 4.
So, the answer is A. 12a^2 + 8a + 4.
(2x-2y)(2y+8) = 4xy - 4y^2 + 16x - 16y.
So, the answer is C. 4xy+16x-4y^2-16y.
(-8q^3 * r^4 * s^2)^2 = (-8)^2 * q^6 * r^8 * s^4 = 64q^6r^8s^4.
So, the answer is C. 64q^6r^8s^4.
-12x^8y^8 / 3x^4y^2 = (-12 / 3) * (x^(8 - 4)) * (y^(8 - 2)) = -4x^4y^6.
So, the answer is A. -4x^4y^6.
Hope this helps!
Your question is a little ambiguous, but I am assuming that you meant to say the function 
Thus, I am solving your question based on assuming the function such as

But, it would still clear your concept, no matter what the function is.
Answer:
we conclude that

The graph is also attached.
Step-by-step explanation:
Given the function

We know that the domain of a function is the set of input or argument values for which the function is real and defined.
As the function has no undefined points nor domain constraints.
Thus, the domain is

Therefore, we conclude that

The graph is also attached.