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garik1379 [7]
3 years ago
12

Find the vertex and focus of the

Mathematics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

Step-by-step explanation:

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3A(48+C)<br> What is the answer
Roman55 [17]

Answer:

144A+3AC

Step-by-step explanation:

I think you provided half of the problem. Because this does not make sense to any problem I can think of.

3 0
3 years ago
4. A construction worker needs to put
serg [7]

Answer:

Step-by-step explanation:

If the window is truly a rectangle then both diagonals are equal. That's one of the properties of a rectangle.

Answer: 10 feet

8 0
2 years ago
Help!! Please im having trouble
bekas [8.4K]

Answer:

1.  5/6 ≥ 2/3

2. 1/5 ≤ 2/8

3. 9/10 ≥ 6/8

4. I can't see it's out of the pic

5. 7/8 ≥ 5/10

6. 2/5 ≥ 2/6

7. 1/3 ≤ 3/8

8. I can't see it's out of the pic.

9. 8/10 ≥ 3/4

10. 3/8 ≤ 11/12

11. 2/3 ≤ 10/12

12. Can't see :(

13. 3/8 ≤ 7/8

14. 2/4 = 4/8

15. 6/8 ≥ 8/12

16. Can't see

Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....

5/6 = approximately 0.83

I hope this helps you! It took forever....



3 0
2 years ago
A card is drawn at random from a well-shuffled pack of 52 cards. Find the probability that the card drawn is neither a red card
Reil [10]
Number of red cards including 2 red queens = 26
Number of black queens = 2
Therefore, number of red cards including 2 red queens and 2 black queens = 26 + 2 = 28
Number of cards neither a red card nor a queen = 52 - 28 = 24

P  =  \frac{ Number \: of \: favourable \: outcomes}{ Total \: numer \: of \: possible \: outcomes}

P (neither \: a \: red \: nor \: a \: queen \: card \: ) =  \frac{24}{52}  =  \frac{6}{13}
8 0
3 years ago
Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .
Masja [62]

Answer:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

Step-by-step explanation:

Lets   y  =  f(x)   in a cartesian coordinates

Having three zeros:

x = -3       ⇒   x  = -2      ⇒   and   x = 1  

That meas that if   x  takes the above mentioned  values " y " must be zero

therefore  y  must be of the form

f (x)  =  y  =  ( x + 3 ) *  ( x +  2 ) * ( x - 1 )     (1)

In that case for y to be zero one of the factors should be zero or

y  =  0        x  + 3 = 0    and  x = - 3  is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x =  3 ,  y have to be 11, therefore we plug in equation (1)  that value to see what happens

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )

11  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1)   =  6*5*2  = 60

Then we adjust the expression (1) to meet the condition of the function passing through point  ( 3 , 11) as:

y  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60    (2)

and check to see if we did right

for y to be zero      x   can be    x = - 3    x  =  -2   and  x = 1 in all these cases y = 0.  And if  x  =  3   in equation (2)  y = 11. And that what we want to shown. Then the solution is:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

8 0
3 years ago
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