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Hoochie [10]
3 years ago
11

E

} - e^{-2} =-2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

$e\cdot e^x -e^{-2}=-2$

$\implies e^{x+1}=e^{-2}-2$

note that RHS is negative. (because e with negative exponent is less than 1)

and LHS is always positive.

so there cannot be any solution

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1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


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