Question

E} - e^{-2} =-2" align="absmiddle" class="latex-formula">

Answer 1

$e\cdot e^x -e^{-2}=-2$

$\implies e^{x+1}=e^{-2}-2$

note that RHS is negative. (because e with negative exponent is less than 1)

and LHS is always positive.

so there cannot be any solution