Answer:
The height of the second cone is 2 <em>h</em>₁.
Step-by-step explanation:
The volume of a cone is:
The volume of the first cone is, <em>V</em>₁ = 5 in³.
The volume of the second cone is, <em>V</em>₂ = 10 in³.
The two cones have the same base diameters.
This implies that the two radii are same, i.e. <em>r</em>₁ = <em>r</em>₂.
Compute the height of the second cone as follows:
Thus, the height of the second cone is 2 <em>h</em>₁.
Answer:
<h2>It is 1</h2>
Step-by-step explanation:
I hope that is useful for you :)
Answer:
v = 23
Step-by-step explanation:
Formatting the question gives;
a = mg - kv² / m
Make v subject of the formula as follows;
(i) Multiply both sides by m
ma = m²g - kv²
(ii) Collect like terms
kv² = m²g - ma
(iii) Divide through by k
v² = (m²g - ma) / k
(iv) Take the square root of both sides
v = √ [(m²g - ma) / k] --------------(ii)
From the question:
a = 2.8
m = 12
g = 9.8
k = 8/3
Substitute these values into equation (i) as follows;
v = √ [(12²(9.8) - 12(2.8)) / (8/3)]
v = √ [(1411.2 - 33.6) / (8/3)]
v = √ [1377.6 / (8/3)]
v = √ [1377.6 x (3/8)]
v = √ [1377.6 x 3 / 8)]
v = √ [516.6]
v = 22.73
v = 23 [to the nearest whole number]
Therefore v = 23 to the nearest whole number
The parabolic motion is an illustration of a quadratic function
The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
<h3>How to model the function?</h3>
Given that:
x stands for time and y stands for height in feet
So, we have the following coordinate points
(x,y) = (5,0), (11,0) and (10,80)
A parabolic motion is represented as:
y =ax^2 + bx + c
At (5,0), we have:
25a + 5b + c = 0
c= -25a - 5b
At (11,0), we have:
121a + 11b + c = 0
Substitute c= -25a - 5b
121a + 11b -25a - 5b = 0
Simpify
96a + 6b = 0
At (10,80), we have:
100a + 10b + c = 80
Substitute c= -25a - 5b
100a + 10b - 25a -5b = 80
75a -5b = 80
Divide through by 5
15a -b = 16
Make b the subject
b = 15a + 16
Substitute b = 15a + 16 in 96a + 6b = 0
96a + 6(15a + 16) = 0
Expand
96a + 90a + 96 = 0
This gives
186a = -96
Solve for a
a = -16/31
Recall that:
b = 15a + 16
So, we have:
b = -15 * 16/31 + 16
b =-240/31 + 16
Take LCM
b =(-240 + 31 * 16)/31
[tex]b =256/31
Also, we have:
c= -25a - 5b
This gives
c= 25*16/31 - 5 * 256/31
Take LCM
c= -880/31
Recall that:
y =ax^2 + bx + c
This gives
y = -16/31x^2 + 256/31x - 880/31
Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31
Read more about parabolic motion at:
brainly.com/question/1130127
