Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is
.
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is


Therefore, the probability is 0.35
Check the attached files for additionals
Answer:
there are 6/8 in 3/4
Step-by-step explanation:
if you want to change the denominator of the fraction, you must find the multiple of it,
(3/4) x 2 is 6/8
so you have 6 x (1/8) thats the same 6/8
3/4 is the minimum simplification, if you want to find the same fraction but with other denominator, you have to multiply 3/4 for any number, to do this you have to multiply the numerator and the denominator
Vicky’s average speed is 0.55m/h
Answer:

Step-by-step explanation:
-This is an LCM problem.
-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

#We introduce the LCM and adjust the fractions based on it :

Hence, the simplified form of the fraction is: 
The price of the new stock would $5.25 because you have to add the $4.75 and $0.50 to find the new price