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stiv31 [10]
4 years ago
10

On your family trip, you used 14 gallons of gas.

Mathematics
1 answer:
Alecsey [184]4 years ago
4 0

Answer:

19

Step-by-step explanation:

To get the total miles you drove first, you need to do 84947 (number after the trip) - 84679 (the number before it. You get 268.

Next you need to find out how many miles per gallon. 268/14 which will equal to 19.142, which you can round to 19.

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Answer:

-10

Step-by-step explanation:

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3 years ago
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Is Figure ABCD congruent to Figure PQRS? Use the drop-down menus to explain your answer. у 6 В. R 4 S a Q N A I Р 8 -6 -4 -2 O -
natali 33 [55]

Answer:

are not and does not

Step-by-step explanation:

7 0
2 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?
Nina [5.8K]
We analyze the chart and observe that the linear function is y=x, since this relation holds for all values in the table.  Drawing this line over the quadratic function shows that they intersect twice, at both the positive and negative x-coordinates.

This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on!  To prove this more rigorously, we can find that the equation of the parabola is y=\frac13 x^2 - 2.  Substituting in y=x, we find that the intersection points occur where \frac13 x^2 - 2 = x, or \frac13 x^2 - x - 2 = 0, or x^2 - 3x - 6 = 0.

This equation doesn't factor nicely, so we use the quadratic formula to learn that x = \frac{3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-6)}}{2} = \frac{3 \pm \sqrt{33}}{2}.  Hence, the x-coordinates of the intersection points are \frac{3 + \sqrt{33}}{2}, which is positive, and \frac{3 - \sqrt{33}}{2}, which is negative.  This proves that there are intersection points on both ends of the axis.
5 0
3 years ago
Which one is the correct answer?
KatRina [158]

\large \sf \pmb{D) \:  \frac{3n}{2}  + 5 \geqslant  - 12  }\\

  • Three time the quotient of a number and 2 increased by 5 is at most -12.
3 0
3 years ago
Read 2 more answers
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