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3 years ago

6

Find the product (3x+8)(x-4)

2 answers:

timurjin [86]3 years ago

7 0

Answer:

3 $x^{2}$ - 4x - 32

Step-by-step explanation:

(3x+8)(x-4)

=3 $x^{2}$ -12x + 8x -32

=3 $x^{2}$ - 4x - 32

balu736 [363]3 years ago

6 0

Answer:

Step-by-step explanation:

3x^2 - 12x + 8x - 32

3x^2 - 4x -32

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Can you help me solve this please

OLga [1]

Answer:

-22+27i

Step-by-step explanation:

$i = \sqrt{ - 1} \\ (3 - 4i)( - 6 + i) \\ = (3 - 4 \sqrt{ - 1} )( - 6 + \sqrt{ - 1} ) \\ = 3( - 6 + \sqrt{ - 1)} - 4 \sqrt{ - 1} ( - 6 + \sqrt{ - 1} ) \\ = - 18 + 3 \sqrt{ - 1} + 24 \sqrt{ - 1} - 4 \\ = - 22 + 27 \sqrt{ - 1} \\ putting \: \: \: \sqrt{ - 1 } = i \\ = - 22 + 27i$

Hope it helps.

Don't forget to click the Brainliest button if you like my answer.

8 0

2 years ago

Cami and Enrique's ages add up to 46. Cami is two years older than three times Enrique's age. How old are Cami and Enrique?

stira [4]

answer:

Cami is 35 and Enrique is 11

35 plus 11 = 46

3 0

3 years ago

Solve for x<br> 5x + 7 = 11<br> Give your answer as a fraction in its simplest form.

Rainbow [258]

Step-by-step explanation:

5x=11-7

5X= 4

X=4/5

=0.8 Answer

6 0

2 years ago

I need help with this

Volgvan

Answer:

72 pi + 48 pi= 120pi (not sure if I am right tho)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

Vesna [10]

Answer:

$c = 11$

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

$a = b= 5$

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

$a + b > c$

$a + c > b$

$b + c > a$

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: $a = b= 5$

$5 + 5 > c$ $===>$ $10 > c$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

The results of the inequality is: $10 > c$ and $c > 0$

Rewrite as: $c > 0$ and $c < 10$

$0 < c < 10$

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

$c = 11$ , since no options are given

8 0

2 years ago