Let s = #small notebooks
Let L = #large notebooks
We Can set up two equations from the info given.
s + L = 6 bought 6 notebooks total
8s + 10L = 56 spent $56
Solve equation 1 for one variable.
L = 6-s
Plug 6-s in equation 2 in place of L
and solve for s
8s + 10(6-s) = 56
8s + 60 - 10s = 56
-2s + 60 = 56
-2s = -4
s = (-4)/(-2)
s = 2
We know s+L = 6 and s=2
2+L = 6
L = 4
4 large notebooks and 2 small notebooks
were purchased
-2<x<3 | *2
-4<2x<6 | +7
3< 2x+7< 13
3<10<13
The answer is C
Answer:
15
Step-by-step explanation:
The calculator is actually correct because he entered division before addition.
Following the Bodmas rule of
B= Brackets O= Off D= Division M= Multiplication A= Addition S= Substraction
And from the question 56÷6 + 3 x 2, when bodmas is applied here it becomes ; (56÷6) +( 3 x2)
And when brackets is removed , it becomes
9+6 = 15.
Hello!
-7 + 9 = x + 1
2 = x + 1
2 - 1 = x
1 = x
I hope this helps you! Have a lovely day!
- Mal
7 x 1/1 = 7 you can also substitute 1/1 with 2/2 ,3/3, 4/4, ext.
