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Romashka-Z-Leto [24]
3 years ago
5

If 1/4 cup of water fills 2/3 of a plastic container, how many cups of water would the full container hold

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
If 1/4 of a cup fills 2/3 we need to find out how much cups 1/3 would fill to do so we multiply 1/4 by 2/3 and we get 2/12 or 1/6 so it can hold 1/4+1/6 cups of water
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Given the recursive formula shown, what are the first 4 terms of the sequence? image Question 19 options: A) 5, 20, 80, 320 B) 5
kvv77 [185]

Answer:

B) 5, 20, 80, 320

Step-by-step explanation:

Complete question

Given the recursive formula shown, what are the first 4 terms of the sequence?

f(1) = 5 if n=1

f(n) = 4f(n-1) if n> 1

A) 5. 25, 100, 400

B) 5, 20, 80, 320

C) 5, 25, 125, 625

D) 5. 14, 60, 236

Get f(2)

f(2) = 4f(2-1)

f(2) = 4f(1)

f(2) = 4(5)

f(2) = 20

Get f(3)

f(3) = 4f(3-1)

f(3) = 4f(2)

f(3) = 4(20)

f(3) = 80

Get f(4)

f(4) = 4f(4-1)

f(4) = 4f(3)

f(4) = 4(80)

f(4) = 320

Hence the first 4 terms of the sequence are 5, 20, 80 and 320

3 0
3 years ago
A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,
Zanzabum

Answer:

$80

Step-by-step explanation:

Area of Mr Jones's yard = 40 * 65 square feet

= 2600 square feet

Mr. Jones was charged $52 for the yard.

Therefore cost per square feet = 52/2600 = $0.02 per square feet

Area of neighbor's yard = 50 * 80 = 4000 square feet

Hence the neighbor will be charged 0.02 * 4000 = $80

For the area corresponding to the yard of size 4000 square feet, he will have to pay $80 to the landscaping company.

6 0
3 years ago
Read 2 more answers
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

4 0
3 years ago
Describe how the graph of y=2x and y=2x+7 are the same.​
MaRussiya [10]

Answer:

These two equations produce a similar graph because they both share the same slope: 2. The only difference is that the y-intercept for the second equation is a positive 7, making the graph shift upwards. Other than this, both equations would be parallel (and identical) on the graph.

4 0
3 years ago
EASY POINTS!!!!!
expeople1 [14]

Answer:

15 - 4 = 11

Step-by-step explanation:

that's literally all it is-

7 0
3 years ago
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