The statements that apply to the ratio of rice and water are:
- The ratio of rice to water is 1 to 2.5
- The ratio of water to rice is 2.5 to 1
<h3>Ratios</h3>
Ratios are used to compare quantities of different measurements
The entries on the table are given as:
<u>Rice Water</u>
2 5
3 7.5
5 12.5
8 20
<h3>The ratios of both quantities</h3>
The ratio (r) of rice and water is then calculated as:
Pick any corresponding table entry.
So, we have:
Divide
This means that, the ratio of rice to water is 1 to 2.5, and the ratio of water to rice is 2.5 to 1
Read more about ratios at:
brainly.com/question/1781657
Answer:
The temperature increased by 15 degrees 6+9=15
Step-by-step explanation:
Hope it helps
Answer:
-4
Step-by-step explanation:
pproblems left is what you will use to determine your slope.
it's -4 because you subtract 4 each time it goes down.
Answer
a) k=7, h=9, the unique solution of the system is 
b) If k=6 and h=8 the system has infinite solutions.
c)If k=6 and h=9 the system has no solutions.
Step-by-step explanation:
I am assuming that the system is x1+3x2=4; 2x1+kx2=h
The augmented matrix of the system is ![\left[\begin{array}{ccc}1&3&4\\2&k&h\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%264%5C%5C2%26k%26h%5Cend%7Barray%7D%5Cright%5D)
. If two times the row 1 is subtracted to row 2 we get the following matrix![\left[\begin{array}{ccc}1&3&4\\0&k-6&h-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%264%5C%5C0%26k-6%26h-8%5Cend%7Barray%7D%5Cright%5D)
.
Then
a) If k=7 and h=9, the unique solution of the system is 
and solviong for 
,
Then the solution is
b) If k=6 and h=8 the system has infinite solutions because the echelon form of the matrix has a free variable.
c)If k=6 and h=9 the system has no solutions because the last equation of the system of the echelon form of the matrix is 
Answer:
x = -3 + i√6 and x = -3 - i√6
Step-by-step explanation:
Let's apply the "completing the square" method to find the roots of this equation.
Take half of the coefficient 6 of x, square it and add this result to x^2 + 6x. Then subtract the same quantity:
x^2 + 6x + 15 becomes
x^2 + 6x + 3^2 - 3^2 + 15 = 0
Rewriting the first three terms as the square of a binomial, we ge:
(x + 3)^2 - 9 + 15 = 0, which simplifies to:
(x + 3)^2 + 6 = 0, or (x + 3)^2 = -6
Taking the square root of both sides:
x + 3 = ±i√6
Then the two roots are complex:
x = -3 + i√6 and x = -3 - i√6
