Question

Find the real solutions of the equation. (2x-6)^2 + 4(2x -6) +3 = 0

Answer 1

Answer:

(

2

x

−

6

)

2

+

4

(

2

x

−

6

)

+

3

=

0

Simplify the left side.

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(

2

x

−

6

)

2

+

8

x

−

21

=

0

Use the quadratic formula to find the solutions.

−

b

±

√

b

2

−

4

(

a

c

)

2

a

Substitute the values  

a

=

4

,  

b

=

−

16

, and  

c

=

15

into the quadratic formula and solve for  

x

.

16

±

√

(

−

16

)

2

−

4

⋅

(

4

⋅

15

)

2

⋅

4

Simplify.

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x

=

4

±

1

2

The final answer is the combination of both solutions.

x

=

5

2

,

3

2

Step-by-step explanation: