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Nesterboy [21]
4 years ago
7

Geometry math question no Guessing and Please show work

Mathematics
2 answers:
tresset_1 [31]4 years ago
8 0

The answer is C 3/2.4

Step2247 [10]4 years ago
6 0
Scale factor is 3/2.4
3/2.4 = 1.25
Prove : 3/1.25 = 2.4
2.4(1.25) = 3
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a plant nursery is growing a tree that is 3 ft tall and grows at an average rate of 1 ft per year. Another tree at the nursery i
Sav [38]
After 2 years. because the first tree will grow 2ft and the second will grow 1ft, which will make them both 5 feet tall
8 0
3 years ago
Help me choose a correct answer​
Tanya [424]

Answer:

y≥-3x+4

Step-by-step explanation:

5 0
3 years ago
What would the graph of<br> Х/4.8 &lt; 1.25 look like?
Rina8888 [55]

Answer:

Step-by-step explanation:

x/4.8 < 1.25                             Multiply both sides by 4.8

4.8 x /  4.8 < 1.25*4/8

x < 6

What this means is that every every number less than 6 is a solution to this inequality.

Graph 32 (shown below is a red area. The important thing to note is that the boundary at 6 is dotted which means it is not included in the solution.

What you want is more closely related to a number line and sort of looks like this

-----o-----o-----o-----o-----o-----o-----o-----o

    -1      0      1       2      3      4      5     6

<===============================o                                                              

Explanation

The top line is the actual number line or the graph

o------- is the way it is made.

The second line are the number divisions of the number line

The third line shows which way the inequality goes and that it is open at 6. Open means that you can get close to 6 but you can't touch 6.

5 0
3 years ago
I don’t know this someone help me
densk [106]

Answer:

i think the answer is 3.14

hope that helped

3 0
4 years ago
Read 2 more answers
Beginning drivers soon learn that bringing an automobile to a stop requires greater distances for higher speeds. A formula that
BaLLatris [955]

The formula for the stopping distance in feet is

d=1.1v+0.055v^2

where v = Speed of the car in miles per hour.

The stopping distance for the car traveling at 15 mph is

d=1.1\times 15+0.055\times 15^2\\\Rightarrow d=28.875\approx 29\ \text{feet}

The stopping distance for the auto traveling at 15 mph is 29\ \text{feet}.

The stopping distance for the car traveling at 30 mph is

d=1.1\times 30+0.055\times 30^2\\\Rightarrow d=82.5\approx 83\ \text{feet}

The stopping distance for the auto traveling at 30 mph is 83\ \text{feet}.

Learn more:

brainly.com/question/19572178

brainly.com/question/24171613

4 0
3 years ago
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