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4 years ago

Geometry math question no Guessing and Please show work

Mathematics

2 answers:

tresset_1 [31]4 years ago

8 0

The answer is C 3/2.4

Step2247 [10]4 years ago

6 0

Scale factor is 3/2.4
3/2.4 = 1.25
Prove : 3/1.25 = 2.4
2.4(1.25) = 3

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What is 4855/200 simplified

EleoNora [17]

Answer:

The answer is 2427.5

Step-by-step explanation:

The fraction consists of two numbers and a fraction bar: 4,855/200

The number above the bar is called numerator: 4,855

The number below the bar is called denominator: 200

The fraction bar means that the two numbers are dividing themselves.

To get fraction's value divide the numerator by the denominator:

Value = 4,855 ÷ 200

To calculate the greatest common factor, GCF:

1. Build the prime factorizations of the numerator and denominator.

2. Multiply all the common prime factors, by the lowest exponents.

Factor both the numerator and denominator, break them down to prime factors:

Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

4,855 = 5 × 971;

4,855 is a composite number;

In exponential notation:

200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;

200 is a composite number;

3 0

3 years ago

Bob's can make 10 hamburgers in 3 minutes. How many

slega [8]

Answer:

3 minutes and 34 seconds

3 0

3 years ago

Read 2 more answers

Evaluate the expression |14 - 7|

slavikrds [6]

The answer to this equation is 7

3 0

3 years ago

Read 2 more answers

Can you please help me. It says to find each product

WITCHER [35]

Answer:

-3/5

Step-by-step explanation:

7 * -3/7 * 1/5

Rewritng

7/7 * -3/5 *1

Simplifying fractions

1 * -3/5 *1

-3/5

5 0

3 years ago

Using Newton's Law of Cooling. You are a medical examiner called to an abandoned house in which a dead body has been discovered.

Artyom0805 [142]

A) The differential equation comes from the fact that the rate of temperature change is proportional to the difference in temperatures.
$\frac{dT}{dt} = \alpha(T -52)$

B) Find general solution by separating variables and integrating $\int\frac{dT}{T-52} = \alpha \int dt \\ ln (T-52) = \alpha t + C \\ T = C e^{\alpha t} +52$ :

C) Initial condition is t=0, T = 87
$87 = C +52 \\ C = 35$

D) Total time elapsed is 10 minutes, new temperature is 84
$84 = 35 e^{10\alpha} +52$
solve for alpha
$e^{10\alpha} =\frac{32}{35} \\ \alpha = \frac{ln(32/35)}{10} \\ \alpha = -.00896$

E) Temperature function is:
$T = 35 e^{-.00896 t} +52$
solving for t
$t = \frac{ln (\frac{T-52}{35})}{-.00896}$
Plug in T = 98.6
$t = -31.95$

This is approximately 32 minutes before he arrived or about 1:20 AM

3 0

3 years ago