Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
Answer:
y= -7x -27
Step-by-step explanation:
Step-by-step explanation:
step 1. I guess we assumed the two lines across the transversal are parallel
step 2. 3x + 1 = 85 (definition of alternate exterior angles)
step 3. 3x = 84 (subtract 1 from each side)
step 4. x = 28. (divide both sides by 3)
<span>1200 = 5000*4r
1200/20000 = r = .06 0r 6%</span>
