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TEA [102]
4 years ago
6

There 64 cards in a pack. Each card is white red or black. The ratio of the number of red cards to the number of black cards is

1:1. 8 red cards are removed from the pack. Find the ratio of the number of red cards now in the pack to the number of black cards now in the pack. Give your answer in its simplest form
Mathematics
1 answer:
iogann1982 [59]4 years ago
8 0
3:4
32:32 to begin with 
24:32, which can be simplified by dividing both sides by 8. 

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8 0
3 years ago
Your math teacher gives you an extra credit problem to figure out her age. Half of her age three years
MatroZZZ [7]

Answer:

Teacher is 27 years old

Step-by-step explanation:

(1/2)(t - 3) = (1/3)(t + 9)

multiply by 6 to clear the fraction

3(t - 3) = 2(t + 9)

Distribute

3t - 9 = 2t + 18

Subtract 2t from both sides

t - 9 = 18

Add 9 to both sides

t = 27

Teacher is 27 years old

6 0
3 years ago
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~ -9 &,& -1~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies 
\begin{cases}
\cfrac{-9+x}{2}=8\\\\
-9+x=16\\
\boxed{x=25}\\
-------\\
\cfrac{-1+y}{2} =14\\\\
-1+y=28\\
\boxed{y=29}
\end{cases}

\bf -------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~10 &,& 12~)
\end{array}\qquad
\\\\\\
\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies 
\begin{cases}
\cfrac{10+x}{2}=6\\\\
10+x=12\\
\boxed{x=2}\\
-------\\
\cfrac{12+y}{2} =9\\\\
12+y=18\\
\boxed{y=6}
\end{cases}
3 0
3 years ago
A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d
UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

                    = 10

5 0
3 years ago
If the confidence level is decreased and the standard deviation and sample size stay the same, then the margin of error will be
Eduardwww [97]

Answer:

true

Step-by-step explanation:

If the standard deviation is increased and the sample size and confidence level stay the same, then the margin of error will also be increased

3 0
3 years ago
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