Timed! Does anyone know this algebra question? Will give brainiest
1 answer:
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Answer:
No. 2/3 of the space to Grano and 1/3 of the space to Wheatie.
Step-by-step explanation:
Allocating about 57% to Wheatie and 43% to Grano, means to allocate 60(.57)=34.2 ft2 of Wheatie and 60(.43)=25.8 ft2 of Grano. In that case there would be 34.2/.4=85.5≈85 boxes of Wheatie and 25.8/.2=129 boxes of Grano. The total profit would be 129(1)+85(1.35)=$243.75
Best option:
200 Granos boxes and 50 Wheaties boxes on the shelf.
200(.2)=40ft^2 will allocate Granos boxes
50(.4)=20ft^2 will allocate Wheaties boxes.
This means that 40/60=2/3=66.6% of the space will allocate Granos boxes and 20/60=1/3=33.3% of the space will allocate Wheaties boxes.
The total profit would be 200(1)+50(1.35)=$267.5
EXTRA:
This is a optimization problem.
Let X1 be the number of Granos boxes
Let X2 be the number of Wheaties boxes
Objective:
Max Z=1(X1)+1.35(X2)
Subjecto to
0.2(X1)+0.4(X2)<=60,
X1<=200,
X2<=120,
X1,X2>=0.
You can solve it using the simplex method. Check the image for more details.
