Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Answer: A 15
Step-by-step explanation:
Answer:
1. Irrational
2. Rational
3. Rational
4. Irrational
5. Irrational
Step-by-step explanation:
In this item, we will be able to form a system of linear equation which are shown below,
292 = 400x + y
407 = 900x + y
where x is the percent of the commission that he gets and y is the wage. The values of x and y from the equations are 0.23 and 200. This means that Justin earns a fixed wage of 200 per day and a commission which is equal to 23%.
Substituting the known values to the equation,
S = (0.23)(3200) + 200 = 936.
Therefore, Justin could have earned $936 had he sold $3,200 worth of merchandise.
1/2 - 2/15= 15-4/30 = 11/30 this means that if you were to add 11/30 to 2/15 is exactly equal to 1/2, to fully answer your question you can use any value above that like 12/30 (keep in mind you have to simplify) = 6/15 = 2/5. But then again your question says to add any number to make it greater than 1/2 so technically you could just add 100 or 200 or 1/2 to make the sum of it greater than one half
