R=square root of volume divided by pi multiply height.
Hope this helps and answers your problem!!!!
Using the normal distribution, there is a 0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
Researching this problem on the internet, the parameters are given as follows:
![\mu = 150, \sigma = 9, n = 10, s = \frac{9}{\sqrt{10}} = 2.85](https://tex.z-dn.net/?f=%5Cmu%20%3D%20150%2C%20%5Csigma%20%3D%209%2C%20n%20%3D%2010%2C%20s%20%3D%20%5Cfrac%7B9%7D%7B%5Csqrt%7B10%7D%7D%20%3D%202.85)
The probability is <u>one subtracted by the p-value of Z when X = 157</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
Z = (157 - 150)/2.85
Z = 2.46
Z = 2.46 has a p-value of 0.993.
1 - 0.993 = 0.007.
0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
More can be learned about the normal distribution at brainly.com/question/15181104
#SPJ1
Ok. No problem. I will answer anything u got
Yes constants stay the same. for example 4x+1. 1 is the constant because it stays the same. and like terms is basically matching. 5y+4x+2x+6y. 5y and 6y matyhch so its 11y+ 4x+2x, 11y+6x. x+ y sdoesnt match.
Answer:
See explanation below (type a 1 (one) in each box)
Step-by-step explanation:
Notice that by using the exponent notation and properties, the given exponents can be re-written and simplified as shown below:
![\frac{(x^{20})^\frac{1}{10} }{\sqrt{x^6} } =\frac{x^2}{x^\frac{6}{2}} =\frac{x^2}{x^3} =\frac{1}{x}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x%5E%7B20%7D%29%5E%5Cfrac%7B1%7D%7B10%7D%20%7D%7B%5Csqrt%7Bx%5E6%7D%20%7D%20%3D%5Cfrac%7Bx%5E2%7D%7Bx%5E%5Cfrac%7B6%7D%7B2%7D%7D%20%3D%5Cfrac%7Bx%5E2%7D%7Bx%5E3%7D%20%3D%5Cfrac%7B1%7D%7Bx%7D)
As you seem to have found. Well done!
What you are expected to do, is to type the coefficient that goes in the numerator (in your case a "1", and in the box below, the exponent that x has in the denominator (in your case also a "1").
So please complete the question as shown below typing a "1" in each box:
![\frac{1}{x^1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%5E1%7D)