1) area of a cicular pool
area of a circle=πr^2 d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2
2) arae of a coin
<span>(if i read it right d=15mm?)
</span>A=πr^2 d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2
Rest all are same problems u try to solve it
I'm guessing you're asking what shape do you get if you cut a hexagon is cut into sixths.
If this hexagon is a regular hexagon, then the shapes would be equilateral triangles.
Answer:
answer D ( if i interpreted your question correctly )
Step-by-step explanation:
Sqrt (c^2) = √(c^2) = C
I think it is a direct variation because if you divide 9/3, 27/3, 39/13, and 60/20 it will all give you the same number which is 3.
I hope this helps.
Answer:
x= 6.5 cm
Step-by-step explanation:
When a tangent line touches the circle, it forms a right angle triangle at that point
Apply the Pythagorean relationship in this case
Given that the height is = 20.2 cm = b
The hypotenuse is = c= x+14.7 cm
General formulae is;
a² +b² =c²
x² + 20.2² =( x+ 14.7)²
x² + 408.04= x² +14.7x+14.7x+216.09
x² + 408.04= x² + 29.4 x +216.09.........................collect like terms
x²-x² + 408.04-216.09= 29.4x
191.95= 29.4x-------------------------------divide by 29.4 t0 get x
191.95/29.4 =x
x=6.5 cm
