EG is the whole thing.
This means that EF + FG = EG
<span>EF=2x-5
</span><span>FG=3x-6
</span><span>EG=19
Now all you do is plug in the numbers.
(2x - 5) + (3x - 6) = 19
5x - 11 = 19
5x = 30
x = 6
Now plug that x into EF and FG.
</span>EF = 2x - 5
EF = 2(6) - 5
EF = 12 - 5
EF = 7
FG = 3x - 6
FG = 3(6) - 6
FG = 18 - 6
FG = 12
So your answers are:
x = 6
EF = 7
FG = 12
<span>d. x = 6, EF = 7, FG = 12</span>
1
7.3
x 9.6
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438
+ 647 0
69. 0 8, hope that helped
Answer:
Step-by-step explanation:
Since area of a circle is pi.r^2
We know that diameter is 20
Radius is half of diameter
So it becomes
Pi.(d/2)^2
So pi.(40/4) is the area of this circle.
Or 40pi/4
I think B I’m
Not
Sue tho so don’t take my word on it but I think it’s B
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
