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Margaret [11]
3 years ago
10

Find a formula for geometric series that begins with 28, 98, 343,...​

Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

Step-by-step explanation:

In a geometric series, the successive terms differ by a common ratio which is determined by dividing a term by the preceding term.

The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio between successive terms in the sequence.

n represents the number of terms in the sequence.

From the seies shown,

a = 28

r = 98/28 = 343/98 = 3.5

The formula representing the nth term of the given sequence would be expressed as

Tn = 28 × (3.5)^(n - 1)

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water stations will be placed every 600 meters of fifteen kilometer race. how many water stations will be needed?
Reika [66]
15 kilometers = 15,000 meters

15,000/600 = 25

So there will be a total of 25 water stations.
8 0
3 years ago
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Solve the equation below for x: <br><br> logx+log(x-2)=log(3x)
Ugo [173]

Answer:

x=5

Step-by-step explanation:

Given equation is

\log\left(x\right)+\log(x-2)=\log(3x)

Apply formula: \log A+\log B=\log\left(AB\right)

\log\left(x(x-2)\right)=\log(3x)

\log\left(x^2-2x)\right)=\log(3x)

Since both sides have equal bases so we can drop the log

x^2-2x=3x

x^2-2x-3x=0

x^2-5x=0

x(x-5)=0

Which gives x=0 and x-5=0

or x=0 and x=5

Original problem \log\left(x\right)+\log(x-2)=\log(3x) is not defined at x=0 henc only x=5 is the final answer.

7 0
4 years ago
Is my answer correct ?
gladu [14]
C is your answer because you count 1 square a block

4 0
4 years ago
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-4(v + 1) = 2(1 - 20) - 6
Flura [38]
17 ish the moon is a little glitch and it looks good but it’s not a problem to get the back up and I have orange juice
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3 years ago
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Find all the zeroes of the equation. x4 – 6x2 – 7x – 6 = 0
NeX [460]

Answer:

-2, 3,  -0.5 + 0.866i,   -0.5 - 0.866i.

Step-by-step explanation:

As the last term is -6 , +/- 2 , +/- 3 are possible zeroes.

Try 2:-

(2)^4 - 6(2)^2 - 7(2) - 6 = -28 so  2 is not a zero.

3:-

(3)^4 - 6(3)^2 - 7(3) - 6 = 0 so 3 is a zero.

(-2)^4 - 6(-2)^2 - 7(-2) - 6 =  0 so -2 is also a zero.

Divide the function by (x +2)(x - 3),  that is  x^2 - x - 6

gives  x^2 + x + 1

x^2 + x + 1

So we have x^2 + x + 1 = 0

x =  [-1 +/- √(1^1 - 4*1*1)] / 2

= -1 + √(-3) / 2 , - 1 - √(-3)  / 2.

= -0.5 + 0.866i, -0.5 - 0.866i

7 0
3 years ago
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