The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
2x=3
Step-by-step explanation:
Hope this helped.
Answer: -6, -3, -2, -1, 1, 2, 3, 6
<u>Step-by-step explanation:</u>
NOTES: p is the last term, q is the coefficient of the first term
Determine all of the factors of p and all of the factors of q
Possible rational roots are all of the combinations of p/q for every factor

Answer:
Step-by-step explanation:
Note that if it has a y- intercept of 20, this means that when x = 0 , y = 20
Find the table which shows that :)