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3 years ago

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In a transformer a 120 volt dc Primary of 500 turns is connected to a secondary of 75 turns. What is the Induced voltage in the

Secondary?

1 answer:

oee [108]3 years ago

7 0

Answer:

The induced voltage in the Secondary is 18 volt.

Explanation:

Given that,

Voltage = 120 volt

Number of turns in primary = 500

Number of turns in secondary = 75

We need to calculate the induced voltage in the Secondary

Using relation number of turns and voltage in primary and secondary

$\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}$

Where, $N_{p}$ = Number of primary coil

$N_{s}$ = Number of secondary coil

$V_{p}$ = Voltage of primary coil

$V_{p}$ = Voltage of primary coil

Put the value into the formula

$\dfrac{120}{V_{s}}=\dfrac{500}{75}$

$V_{s}=\dfrac{120\times75}{500}$

$V_{s}=18\ Volt$

Hence, The induced voltage in the Secondary is 18 volt.

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Answer:

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Explanation:

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In our problem the value of $n$ will be the same for both cases. Also, $R$ is the gas constant.

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Also, we have $V_2=22V_1$ from the question.

$\frac{P_2\times 22V_1}{P_1V_1}=\frac{T_2}{T_1}\\\\\frac{P_2\times 22}{P_1}=\frac{T_2}{T_1}$

We need to convert the temperature from $\°C$ to Kelvin.

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Plug these values we get,

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