The answer is 10.5 kg m/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a
Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt
So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)
It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s
I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
2 j x b
H c e c hope this helppppsssssssss
<u>Solution and Explanation:</u>
The following calculation is made in order to find out the area and the final velocity vector.
Using the given information and the data in the question,
m1u1 + m2u2 = (m1 + m2) multiply with v
40000 multiply with ( -20i ) + 60000 multiply with ( 10j ) = 100000 multiply with v
Therefore, v = -8i + 6j
That is |v| = 10 knots towards the 36.86 degree north of the west
Power is the rate at which work is done (2nd option)
Precisely around 1,800 miles below.