All categories

3 years ago

How did you use science for your summer vacation? List ideas

1 answer:

4 0

You could observe stuff like how many inches of rain we got or how many flowers are growing or how was the weather Monday through Friday .also by looking outside of Simply observing the weather outside in the nature

You might be interested in

. What animal did scientists study to create the brain–machine interface?

antiseptic1488 [7]

Monkey

Explanation: HOPE IT HELPS

7 0

3 years ago

Read 2 more answers

5. Calculate the number of grams in a sample<br> of 1.025 moles of MgCO,.

snow_lady [41]

Answer:

41/40

Explanation:

3 0

3 years ago

what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th

serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

Xe + 2F₂ ⇒ XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3 the amount of F increased.

131.3 g of Xe ------------------ 207 g of XeF₄

130 g of Xe ------------------- x

x = (130 x 207) / 131.3

x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0

3 years ago

PLS HELP! Suppose you have a sample of an unknown mineral with a mass of 86 g. You place the sample in a graduated cylinder fill

bija089 [108]

O le elo ma muli pipilo ma le kaoga e fai gi o meaoga

4 0

3 years ago

A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3. Determine the equilibrium pressure of NO2 if Kp for the reac

dlinn [17]

Explanation:

Reaction equation for this reaction is as follows.

$NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)$

It is given that $K_{p}$ = 0.0118.

According to the ICE table,

$NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)$

Initial: 0.86 0.86 0 0

Change: -x -x +x +x

Equilibrium: 0.86 - x 0.86 - x x x

Hence, value of $K_{p}$ will be calculated as follows.

$K_{p} = \frac{P_{NO_{2}} \times P_{SO_{3}}}{P_{NO} \times P_{SO_{3}}}$

0.0118 = $\frac{x \times x}{(0.86 - x)^{2}}$

x = 0.084 atm

Thus, we can conclude that $P_{NO_{2}}$ is 0.084 atm.

4 0

4 years ago