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2 years ago

15

In the reaction, Hydrogen + Iodine --> Hydrogen Iodide at equilibrium, some Iodine is is added. What happens to the equilibri

um?

1 answer:

Fantom [35]2 years ago

6 0

Answer:

the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.

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Example of obtuse angle

marishachu [46]

Answer:

when the degree is less than 90

8 0

3 years ago

Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh

Svet_ta [14]

Answer: The freezing point depression is $1.86^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=K_f\times m$

$\Delta T_f$ = Depression in freezing point

$K_f$ = freezing point constant = $1.86^0C/m$

m= molality = $\frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m$

$\Delta T_f=1.86mol/kg^0C\times 1m$

$\Delta T_f=1.86^0C$

Thus freezing point depression is $1.86^0C$

3 0

2 years ago

B) How many kilograms of carbon dioxide are formed when 24.42 g of iron is<br> produced?

charle [14.2K]

Answer:

0.0289 kg of CO2 will be formed

Explanation:

Step 1: Data given

Mass of iron produced = 24.42 grams

Atomic mass iron = 55.845 g/mol

Molar mass CO2 = 44.01 g/mol

Step 2: The balanced equation

Fe2O3 + 3CO → 2Fe + 3CO2

Step 3: Calculate moles iron

Moles iron = mass iron / molar mass iron

Moles iron = 24.42 grams / 55.845 g/mol

Moles iron = 0.437 moles

Step 4: Calculate moles CO2

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.437 moles Fe we'll have 3/2 * 0.437 = 0.6555 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.6555 moles * 44.01 g/mol

Mass CO2 = 28.85 grams = 0.0289 kg

0.0289 kg of CO2 will be formed

5 0

3 years ago

Quis critérios foram usadps por dobereiner em sua tentava de organiza os elementos químicos?

anyanavicka [17]

Döbereiner grouped the known elements into <em>triads</em> (sets of three) so that

• The <em>atomic mass of the middle element</em> was approximately the average of the other two

• The <em>chemical properties of the middle element</em> were between those of the other two

• The <em>physical properties of the middle element</em> were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

(c) Melting point of Na = 371 °C.

Average melting point of Li and K = (454 °C + 330 °C)/2 = 784 °C/2

= 392 °C

8 0

2 years ago

If an experiment calls for 0.200mole acetic acid (Hc2H3O2)how many grams of glacial acetic acid do we need?

bija089 [108]

<h3>Molar mass:-</h3>

$\\ \sf\longmapsto HC_2H_3O_2$

$\\ \sf\longmapsto 1u+2(12u)+3(1u)+2(16u)$

$\\ \sf\longmapsto 1u+24u+3u+48u$

$\\ \sf\longmapsto 28u+48u$

$\\ \sf\longmapsto 76u$

$\\ \sf\longmapsto 76g/mol$

No of moles=0.2mol
Given mass=?

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}$

$\\ \sf\longmapsto 0.2=\dfrac{Given\:mass}{76}$

$\\ \sf\longmapsto Given\:Mass=0.2\times 76$

$\\ \sf\longmapsto Given\:Mass=1.52g$

7 0

3 years ago