Foil the binomials
First: n*n=n^2
Outer: n*-5=-5n
Inner: -3*n=-3n
Last: -3*-5=15
Put it together and simplify
n^2-5n-3n+15
n^2-8n+15
Final answer: A
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer:
18,751
Step-by-step explanation:
18 234 . 9
516 . 1
----------------
18 751 . 0
----------------
Answer: Perimeter = 40
Area = 204
Step-by-step explanation:
Perimeter is the sum of all the sides:
11 + 12 + 17 = 40
The area of a triangle is 1/2 base x height
1/2( 17 x 24)
1/2( 408) = 204
Answer:
8,5,2
Step-by-step explanation:
8 , 5, 2 Just use rigorous trial and error
