Pls i don't understand :'( PLS

Mathematics

2 answers:

rewona [7]3 years ago

7 0

The area of a trapezoid is
A= h(b1+b23)÷2
First you add the bases and then you multiply by the height and the result divide by 2. Hope it was usefull

raketka [301]3 years ago

3 0

A= 28 because you have to do base1+ base2 then dived by 2 after that you have to multiply with hight

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the math competition had 108teams on the first day. on the second day there were 10 less teams than on the first day how many te

Zolol [24]

What you would do here is subtract.
The first day had 108 teams, and the second day had 10 less teams. 108-10 is 98, so there were 98 teams on the second day.

7 0

3 years ago

Read 2 more answers

Simplify radicals problems attached please help!

Finger [1]

Answer:

G7. (2√3)/3

G8. -2+√7

G9. (6 +2√2 -3√3 -√6)/7

Step-by-step explanation:

G7.

$\dfrac{2}{\sqrt{3}}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}$

G8.

$\dfrac{3}{2 +\sqrt{7}}=\dfrac{3}{2+\sqrt{7}}\cdot\dfrac{2-\sqrt{7}}{2-\sqrt{7}}=\dfrac{6-3\sqrt{7}}{2^2-(\sqrt{7})^2}\\\\=\dfrac{6-3\sqrt{7}}{-3}=\sqrt{7}-2$

G9.

$\dfrac{2-\sqrt{3}}{3-\sqrt{2}}=\dfrac{2-\sqrt{3}}{3-\sqrt{2}}\cdot\dfrac{3+\sqrt{2}}{3+\sqrt{2}}=\dfrac{(2-\sqrt{3})(3+\sqrt{2})}{9-2}\\\\=\dfrac{6+2\sqrt{2}-3\sqrt{3}-\sqrt{6}}{7}$

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<em>Comment on the problems</em>

In most cases, these expressions are the simplest possible (take the least amount of ink to draw, and take the fewest math operations to evaluate). What seems to be intended is that the denominator be made a rational number. This is done by multiplying the given fraction by a fraction equal to 1 that has the same denominator but with the sign of the radical reversed (unless, as in the first case, the radical is by itself).

The purpose of doing this is to take advantage of the fact that (a-b)(a+b) = a²-b², so if "a" or "b" is a square root, that root will not be seen in the product. In problem G9, we see this can make the numerator quite messy--not exactly a simpler form--but all the irrational numbers are in the numerator.

8 0

3 years ago

Can someone help me with these? I need some help.

nata0808 [166]

Answer:

1) $\sqrt{569}$ 2) 8 3) 0.8 4) $\sqrt[10]{61}$