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2 years ago

In what way can a political party be classified as a linkage institution?

Mathematics

1 answer:

Natali5045456 [20]2 years ago

7 0

Answer:

A political party is a linkage institution that is characterized by a group of people joined together by common philosophies.

Step-by-step explanation:

The main goal of a political party is to nominate individuals to get elected to local, state, and national offices in order to develop and implement public policy.

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What is the answer to the problem 16g +20h with the distributed property applied

e-lub [12.9K]

36 g I’m pretty sure that’s the answer

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3 years ago

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What rule is this, please answer correctly, please

hichkok12 [17]

Answer:

Reflection

Step-by-step explanation: It is reflection because it is the same thing just reflected

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2 years ago

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Can someone do eight nine one and two ?

Sergeeva-Olga [200]

Answer: hello there here are your answers:

8) B multiplication property of zero

9) C additive identify

1) 8

2) -2a-7

Step-by-step explanation:

1) $\frac{3+u}8^{2} \\u=5 \\so\\ \frac{3+5}8^{2} \\3+5=8^{2} \\8^{2} =\\64 \\\\ 64/8=\\\\\\8 \\there.\\\\\\$

2) $-2(a-7)\\\\-2(a)(-7)\\\\=-2a+14\\\\\\there$

5 0

2 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Angle θ = x

Adjacent Leg = 5.8

Hypotenuse = 7.3

Step 2: Solve for x

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

8 0

2 years ago

Please help with 6 and 7

Maru [420]

Answer:

6a) i- 2hrs 36mins ii- 3hrs 12mins

b) car A≈ 76.9km/h car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km car B=60km

c) 30km

d) car A≈36mins car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0

3 years ago