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4 years ago

9

A 12 foot ladder is leaning against the side of a building. The top of the ladder reaches 10 feet up the side of the building. A

pproximately how far is the bottom of the ladder from the base of the building.

1 answer:

Soloha48 [4]4 years ago

5 0

√135=3√15.....................

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The population of a town increased from 3450 in 2006 to 4650 in 2011. Find the absolute and relative (percent) increase.

netineya [11]

Answer:

15% increase per year.

Step-by-step explanation:

5,600 - 3,500 = 2,100

2,100 is what percent of 3,500?

2,100 = X*3,500

X = 2,100 / 3,500

X = .60 or 60%

An average of 15% increase per year.

4 0

3 years ago

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

3 years ago

3x+8 •59 solve for x

Marina86 [1]

1) Let's solve for x, writing this equation.

3x +8*59 =0

3x +472=0 <em>Subtract 472 from both sides</em>

3x = -472

x= -472/3 or -157.33

2) So the answer is x= -472/3

6 0

1 year ago

Jacinta borrowed sh. 100,000 from her cooperative society. She pays 1% interest of the outstanding balance every month. If she p

vredina [299]

The amount of money that Jacinta pays to service the whole loan as interest is <u>sh. 5,899</u>.

<h3>What is interest?</h3>

Interest is the finance charge that a borrowers incurs to service a loan.

Interest is based on the outstanding balance at the end of the payment period.

<h3>Data and Calculations:</h3>

Principal loan = sh. 100,000

Interest on outstanding balance = 1%

Monthly payment of principal and interest = sh. 10,000

Period of repayment = Monthly

<h3>Amortization Schedule:</h3>

Beginning Interest Payment Ending Balance

1st month sh. 100,000 sh. 1,000 sh. 10,000 sh. 91,000

2nd month sh. 91,000 sh. 910 sh. 10,000 sh. 81,910

3rd month sh. 81,910 sh.819 sh. 10,000 sh. 72,729

4th month sh. 72,729 sh. 727 sh. 10,000 sh. 63,456

5th month sh. 63,456 sh. 636 sh. 10,000 sh. 54,092

6th month sh. 54,092 sh. 541 sh. 10,000 sh. 44,633

7th month sh. 44,633 sh. 446 sh. 10,000 sh. 35,079

8th month sh. 35,079 sh. 351 sh. 10,000 sh. 25,430

9th month sh. 25,430 sh. 254 sh. 10,000 sh. 15,684

10th month sh. 15,684 sh. 157 sh. 10,000 sh. 5,841

11th month sh. 5,841 sh. 58 sh. 5,899 sh. 0

Total interest paid = sh. 5,899

Thus, based on the payment schedule above, the amount of money that Jacinta pays to service the whole loan as interest is <u>sh. 5,899</u>.

Learn more about loan interests at brainly.com/question/24576997

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8 0

2 years ago

Pls help me with this question.

maw [93]

Answer:

The slope for this equation is $\frac{1}{7}$ .

Step-by-step explanation:

x y

point 1: -4 -3

point 2: 3 -2

slope: $\frac{1}{7}$

To solve for slope here is an equation, to help: $\frac{y^2-y^1}{x^2-x^1}$

$\frac{y^2-y^1}{x^2-x^1} \\\\\frac{-2-(-3)}{3-(-4)} \\\\= \frac{1}{7} \\$

5 0

3 years ago