For example, sinD = 7/25; cosD = 24/25; tgD = 7/24;
Answer:
no
Step-by-step explanation:
The correct answer is d equals 1
Answer:
Packaging with cube will be more efficient.
Step-by-step explanation:
Given:
A cube and a sphere where the diameter of the sphere is equal to the height of the cube.
Let the height of the cube "x"
Radius of the sphere =
Formula to be used:
Surface area of the cube =
and Surface area of the sphere = ![4\pi (r)^2](https://tex.z-dn.net/?f=4%5Cpi%20%28r%29%5E2)
Volume of the cube =
and Volume of the sphere = ![\frac{4\pi r^3}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D)
We have to compare the ratio of SA and Volumes.
Ratio of SA : Ratio of their volumes :
⇒
⇒ ![\frac{Volume \ of \ cube\ (V_1)}{Volume\ of\ sphere\ (V_2)}](https://tex.z-dn.net/?f=%5Cfrac%7BVolume%20%5C%20of%20%5C%20cube%5C%20%28V_1%29%7D%7BVolume%5C%20of%5C%20sphere%5C%20%28V_2%29%7D)
⇒
⇒ ![\frac{x^3}{\frac{4 \pi r^3}{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%7D%7B%5Cfrac%7B4%20%5Cpi%20r%5E3%7D%7B3%7D%20%7D)
⇒
⇒ ![\frac{x^3}{\frac{4 \pi (\frac{x}{2})^3}{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%7D%7B%5Cfrac%7B4%20%5Cpi%20%28%5Cfrac%7Bx%7D%7B2%7D%29%5E3%7D%7B3%7D%20%7D)
⇒
⇒ ![\frac{x^3}{\frac{4 \pi (\frac{x^3}{8})}{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3%7D%7B%5Cfrac%7B4%20%5Cpi%20%28%5Cfrac%7Bx%5E3%7D%7B8%7D%29%7D%7B3%7D%20%7D)
⇒
⇒ ![\frac{6}{\pi}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%5Cpi%7D)
⇒ approx
⇒ approx ![2](https://tex.z-dn.net/?f=2)
⇒
⇒ ![V_1=2V_2](https://tex.z-dn.net/?f=V_1%3D2V_2)
Packaging of the toy with the cube will be more efficient as it has more volume comparatively.
Answer:
-01/0/0.8/1.2/1.6
Step-by-step explanation: