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3 years ago

Can distributive property be used to rewrite 6 x (10 - 5)?

Mathematics

2 answers:

kirza4 [7]3 years ago

8 0

Answer:

Yes

Step-by-step explanation:

6(10 - 5)

Can be written as

6(10) - 6(5)

Both simplify to 30

Luden [163]3 years ago

6 0

Answer:

Step-by-step explanation:

6(10-5)=60-30=30

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On Friday, a fruit stand sold a total of 92 apples and oranges. On Saturday, the fruit stand sold four times the number of apple

andreev551 [17]

Option A : a+o = 92 , 4a+2o = 284 is the right answer

Step-by-step explanation:

Let o be the number of oranges sold on Friday and

a be the number of apples sold on Friday

So,

A total of 92 was sold on Friday will yield the equation

$a+o = 92$

On Saturday,

4 times the number of apples = 4a

2 times the number of oranges = 2o

So,

$4a+2o = 284$

Hence,

The system of equations is:

$a+o = 92\\4a+2o = 284$

Option A : a+o = 92 , 4a+2o = 284 is the right answer

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$