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bagirrra123 [75]
3 years ago
11

Standard form of 4+5/10+7/100+9/1000

Mathematics
2 answers:
Sonbull [250]3 years ago
6 0
<span>the answer in standard form is 4.579</span>
Ymorist [56]3 years ago
3 0
9/17/109/1000 is your answer to your question
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Write the equation of the line thay passes through the point (2,-1) and has a slope of -3​
disa [49]

Answer:

Y = -3x - 1

Step-by-step explanation:

Y= mx + b

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3 0
3 years ago
Find the lateral surface area of the figure.
Brut [27]

Surface area of the cylinder = 816.4 sq. ft.

Solution:

Height of the cylinder = 21 ft

Diameter of the cylinder = 10 ft

Radius of the cylinder = 10 ÷ 2 = 5 ft

Use the value of \pi = 3.14

Surface area of the cylinder = 2 \pi r h+2 \pi r^{2}

Substitute the given values in the surface area formula, we get

Surface area of the cylinder $=2\times3.14\times 5\times 21+2 \times3.14\times 5^2

                                               =659.4+157

                                               =816.4 ft²

Hence the surface area of the cylinder is 816.4 sq. ft.

7 0
3 years ago
Read 2 more answers
a circle with a radius of 1 cm sits inside a 3cm x 3cm rectangle. What is the area of the shaded region (the rectangle is shaded
masha68 [24]

Answer:

The area of the shaded region is 5.86\ cm^{2}

Step-by-step explanation:

we know that

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so

A=b^{2} -\pi r^{2}

we have

b=3\ cm

r=1\ cm

assume

\pi =3.14

substitute the values

A=3^{2} -(3.14)(1)^{2}

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5 0
3 years ago
Read 2 more answers
How do you write a word form for 4.293
pychu [463]
Four and two hundred ninety-three thousandths
5 0
3 years ago
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Hi please help with a few (mean, median) math questions!
sattari [20]
1.rearrange your data from least to greatest:
<span>0,0,1,1,2,2,2,14 </span>

middle is 1 and 2 ... so median is 1+2/2= 1.5 and  it is the  median not the mean
2.I believe the only outlier is 50. Finding the mean would be 80.11.
<span>The answer would be D
</span>3.D. Mean always goes toward the skewness due to outliers.
<span>Median is minimally affected by outliers.
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3 0
3 years ago
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