the answer is d
i know thiis because i used google hehe
Answer:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12
Explanation:
Cl2, reacts with 55g of CS2. How much CC14 is produced? CS2 +3 Cl2 —-> CCl4 +S2C12 sike firgue it out on your own
Answer:
I think it's Trinitrogen Pentaseleniumide
Explanation:
Tri - three
Penta - five
Second element ends with -ide
Answer: 0.52 L of 15 M will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base