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Alenkasestr [34]

3 years ago

7

What is the amount of energy carried by a photon that has a frequency of 3.76 x 1014 Hz?

2 answers:

Vaselesa [24]3 years ago

6 0

C = λν E = hν. C = 3.00 x 108 m/s h = 6.626 x 10- 34 J-s (or J/Hz). What is the wavelength of a wave having a frequency of 3.76 x 1014 s-1?

VARVARA [1.3K]3 years ago

4 0

(3.0x108)/(3.76x1014) =7.98x10-7 m

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A Compound Contains Two or more _______.

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A compound contains two or more elements chemically combined

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The time required for one-half of the atoms from a sample of a radioactive substance to decay is called its _____.

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A.) half - life of a radioactive substance is defined as the time during which concentration of the substance becomes half the initial value.

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Suppose that 0.48 g of water at 25∘C∘C condenses on the surface of a 55-gg block of aluminum that is initially at 25∘C∘C. If the

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Answer : The final temperature of the metal block is, $25^oC$

Explanation :

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of aluminum = 55 g

$m_2$ = mass of water = 0.48 g

$T_{final}$ = final temperature = ?

$T_1$ = temperature of aluminum = $25^oC$

$T_2$ = temperature of water = $25^oC$

$c_1$ = specific heat of aluminum = $0.900J/g^oC$

$c_2$ = specific heat of water= $4.184J/g^oC$

Now put all the given values in equation (1), we get

$55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]$

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3 years ago

What is oxidation number of S in H2SO5??

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★ « <em><u>what is oxidation number of S in H2SO5??</u></em><em><u> </u></em><em><u>»</u></em><em><u> </u></em><em><u>★</u></em>

<em><u>it's </u></em><em><u> </u></em><em><u>6</u></em><em><u>!</u></em><em><u>!</u></em>

Explanation:

<em>Oxidation number of S in H2SO5 is 6 .</em>

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2 years ago

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1. A gas having the following composition is burnt under a boiler with 50% excess air.

jeka94

The composition of the stack gas are :

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of $CH_4$ : 70% of 100 g = 70 g

Mass of $C_3H_8$ : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

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Hence, composition of the stack gas are:

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$C_3H_8$ = 0.0202

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