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GalinKa [24]
3 years ago
8

Describe the properties of noble gases. Based on their electronic arrangement, explain whether they can exist alone in nature.

Chemistry
1 answer:
Firdavs [7]3 years ago
5 0

Answer:

they have a full outer shell, and cannot live alone In nature as they cannot bind with other gases

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11.23 mm = ____ m 1,123 m 0.01123 m 0.1123 m 11,230 m
kaheart [24]
For every meter, the equivalent measurements is 1000 millimeters. Hence in the problem where the number of millimeters is given, we divide the number by 1000 to get the number of meters. The answer here is 0.01123 m.
3 0
3 years ago
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Which of the following is an example of qualitative observation?Select one of the options below as your answer:. A. Joseph is ob
vekshin1
<h2>Answer : Option C) Joseph is observing the color of the reaction mixture to see whether proteins are present in the given solution.</h2><h3>Explanation :</h3>

An example of qualitative observation is the one where one uses the five senses to identify the changes in the reaction.

Here, when Joseph is studying a reaction mixture he is trying to observe a color change which will confirm that there is proteins present in the reaction mixture or not If there is a color change observed then it will confirm the presence of proteins.

Usually qualitative observations are those which can be easily predicted by using five senses.


5 0
3 years ago
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How does the type of chemical bonds present in a substance affect the substances properties?
SCORPION-xisa [38]
Once a chemical bond is formed, the atoms are rearranged to form a stronger bond, affecting the hardness, malleability, etc. The stronger the bond, the easier a substance will break, or, if its a liquid, it will resist seperation.
8 0
3 years ago
Cual es mi nombre ? me pide en mi examen de kinder :(
erastova [34]

Answer:

dude

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3 0
3 years ago
A student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.
kvasek [131]

Answer:

1 cm/s

Explanation:

From the question given above,

the student is trying to convert 0.010 m/s to a number in cm/s.

Thus, we can convert 0.010 m/s to cm/s as illustrated below:

Recall:

1 m/s = 100 cm/s

Therefore,

0.010 m/s = 0.010 m/s × 100 cm/s ÷ 1 m/s

0.010 m/s = 1 cm/s

Therefore, 0.010 m/s is equivalent to 1 cm/s

8 0
3 years ago
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