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AlexFokin [52]
3 years ago
8

kelly subscribes to a service called mysongs for downloading music she pays a $7 fee each month to download an unlimited numbers

of songs at $0.20 each last month kelly's bill was $23.80
Mathematics
1 answer:
Nastasia [14]3 years ago
8 0

subtract the fee from the total to get the amount actually spent on songs

23.80-7 = 16.80

 divide that amount by price per song to get number of songs downloaded

16.80 /0.20 = 84 songs

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2. Diamond has $350 in her bank account. She
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$173.70 will be the balance

Step-by-step explanation:

350 - (4*18.45) - (2*51.25)

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Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in
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Given f(x)=\frac{-1}{4}(x+4)^2-8.

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The average rate of change of the function  f(x) on interval [-2,2] is

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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
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\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

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Answer: f(x) is just a fancy way of writing y in an equation

Step-by-step explanation:

Example: f(x)= 2x+4 is the same as y= 2x+4

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