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Fynjy0 [20]
3 years ago
15

the function f(x)=-2cos(3x-pi/4) has. . a. amplitude 3 and period pi. b. amplitude 2 and period 2pi/3. c. amplitue 3 and period

2pi. d. amplitude 3 and period 4pi
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0
Form of the function:
y = a cos ( b x + c )            a = -2, b = 3
where amplitude is | a | = |-2 | = 2
and period: T = 2π/b = 2π/3
Answer: B ) amplitude 2 and period 2π/3
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Triangle congruence... SAS SSS AAS ASA pls explain why
abruzzese [7]

Answer:

it is SAS

Step-by-step explanation:

because BC is common side in both triangles

so

now two triangles have 2 sides equal and 1 angle equal so

it is congruent by SAS rule

4 0
3 years ago
The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour
vitfil [10]

Z value is a numerical  measurement that describe a value relationship to the mean of a group of values. The standard deviations is 1.25 above the mean is 14,500 hours.

<h3>Given information-</h3>

The mean for the bulb is 12,000 hours.

The standard deviation for the bulb is 2000 hours.

Sample value is 14500.

To find out the how many standard deviation is 14500 mean away from the mean the z value of the mean should be calculated.

<h3>Z value</h3>

Z value is a numerical  measurement that describe a value relationship to the mean of a group of values. Z value is the ratio of the difference of the sample value x and mean \mu to the standard deviation. Thus the z value for the given mean \sigma is,

z=\dfrac{x-\mu}{\sigma}

z=\dfrac{14500-1200}{2000}

z=1.25

Thus the standard deviations is 1.25 above the mean is 14,500 hours.

Learn more about the z value here;

brainly.com/question/62233

4 0
3 years ago
Determine the x-intercept and y-intercept of the following linear equations
Blizzard [7]

Answer:

Step-by-step explanation:

the x intercept takes coordinate (x,0)

the y intercept takes coordinate (0,y)

                                         x intercept                        y intercept

40: x+y=5                          (5,0)                                      (0,5)

x=0 , y=5, when y=0 x=5

41: x-y=5                            (5,0)                                      (0,-5)

x=0, -y=5 then y=-5, when y=0, x=5

42: 3x+4y=12                     (4,0)                                      (0,3)

x=0, 4y=12⇒y=12/4⇒y=3

y=0, 3x=12⇒x=12/3⇒x=4

43: 2x+3y=6                      (3,0)                                       (0,2)

x=0 , 3y=6⇒y=6/3=2

y=0 ,3y=6 ⇒ y=6/3 ⇒y=2

44: 3x+4y=-24                   (-8,0)                                      (0,-6)

x=0 , 4y=-24⇒y=-24/4 ⇒ y=-6

y=0 , 3x=-24⇒ x=-24/3⇒x=-8

45: 1/3x+2/3y=5/6            (5/2,0)                                    (0,5/4)

x=0 , 2/3 y=5/6 ⇒12y=15 ⇒ y=15/12 ⇒y=5/4

y=0 , 1/3 x=5/6 ⇒6x=15 ⇒x=15/6 ⇒x=5/2

46: x=-2                             (-2,0)                                   no y intercept

it is vertical line , there is no y intercept

47: y=15                    no x intercept                               (0,15)

horixzontal line, no x intercept

48: 3x-7y=8              (8/3,0)                                             (0,-8/7)

x=0 , -7y=8 ⇒y=-8/7

y=0 , 3x=8 ⇒x=8/3

7 0
4 years ago
How to factor X^2+2x+6
Trava [24]
Its (x+1−√<span><span><span><span>​5</span>​<span>​​</span></span>ı)(x+1+<span>√<span><span>​5</span>​<span>​​</span></span></span>ı)</span><span>
</span></span>
7 0
3 years ago
Read 2 more answers
I) Coordinates of point P
SSSSS [86.1K]

Given:

Five points P, Q, R, S ,T on a coordinate plane.

To find:

The coordinates of (i) P, (ii) Q, (iii) T, (iv) (Ordinate of T) – (Abscissa of R) and (v) (Abscissa of Q) – (Ordinate of S).

Solution:

From the given graph it is clear that the coordinates of given points are

P = (1,1)

Q = (-3,0)

R = (-2,-3)

S = (2,1)

T = (4,-2)

(i)

Coordinates of point P are (1,1).

Therefore, the correct option is (a).

(ii)

Coordinates of point Q are (-3,0).

Therefore, the correct option is (b).

(iii)

Coordinates of point T are (4,-2).

Therefore, the correct option is (c).

(iv)

Ordinate is y-coordinate and abscissa is x-coordinate.

Ordinate of T = -2

Abscissa of R = -2

(Ordinate of T) – (Abscissa of R) = -2 - (-2)

                                                     = -2 + 2

                                                     = 0

Therefore, the correct option is (c).

(v)

Abscissa of Q = -3

Ordinate of S = 1

(Abscissa of Q) – (Ordinate of S) = -3 - 1

                                                      = -4

Therefore, the correct option is (a).

8 0
3 years ago
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