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krok68 [10]
3 years ago
13

How to use unit circle to evaluate the six trig functions of theta

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
All you need to know is that sin(x) is the y-value of the coordinate point and cos(x) is the x-value of the coordinate point. From here, tan(x) is just sin(x)/cos(x).
That's three of them already. sec(x) is 1/cos(x), csc(x) = 1/sin(x) and cot(x) = 1/tan(x).
Just to recap:

cos(x) = x-value
sin(x) = y-value
tan(x) = \frac{sin(x)}{cos(x)}
csc(x) =  \frac{1}{sin(x)}
sec(x) = \frac{1}{cos(x)}
cot(x) =  \frac{1}{tan(x)} =  \frac{cos(x)}{sin(x)}

And you are done!
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If f(x) = 2x + 6 and g(x) = -4x - 8 find f(g(x)) = ?x+?
amm1812

hope it helps

plz mark brainliest

6 0
3 years ago
F(x) = 4x f(x) = −x + 5 what is the solution
vagabundo [1.1K]
As function is = 4x
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6 0
4 years ago
What is (6.89+14.52)+(-14.52)???
MrRa [10]
The answer is 6.89 because
6.89+14.52=21.41
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7 0
4 years ago
Plzzzz help and I'll give you brainliest ​
sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

4 − 12 sin² θ cos² θ

4 − 3 (2 sin θ cos θ)²

Double angle formula:

4 − 3 (sin (2θ))²

4 − 3 sin² (2θ)

Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

4 − 3 + 3 cos² (2θ)

1 + 3 cos² (2θ)

3 0
3 years ago
Write an equation for a parabola with a focus (-3,6) and a directrix y=0
Airida [17]

Answer:

A= 1/12

Step-by-step explanation:

just look up your question online and click on the first link and it will tell you all the answers you need :)

7 0
3 years ago
Read 2 more answers
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