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Semmy [17]
3 years ago
9

What is 4.95 +4883.83

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0
Remember to care th 1
0001.00
4883.83
   + 4.95
--------------
 4888.78

Allisa [31]3 years ago
5 0
4888.78  is the sum of 4.95 and 4883.83
 
          4.95
 + 4883.83
____________
    4888.78

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I need help, can someone help
saw5 [17]
The answers on the right are in reverse order to the questions on the left.

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7 0
3 years ago
Professor Liu gave the same quiz to the students in her morning class and in her afternoon class. The average (arithmetic mean)
natka813 [3]

Answer:

Afternoon class has more students.

Step-by-step explanation:

Let m be the number of students in the morning class and n be the number of students in the afternoon class.

The average score for the students in the morning class was 80, then the sum of their scores is 80m.

The average score for the students in the afternoon class was 86, then the sum of their scores is 86n.

The sum of the scores of both classes is

80m+86n

and the average score is

\dfrac{80m+86n}{m+n}

The average (arithmetic mean) score for the two classes combined was 84, then

\dfrac{80m+86n}{m+n}=84\\ \\ 80m+86n=84m+84n\\ \\86n-84n=84m-80m\\ \\2n=4m\\ \\n=2m

This means n is greater, so afternoon class has more students.

7 0
3 years ago
Investment of $2000 at 10% simple interest for 9 years
Oliga [24]

Answer:

The last investment (C) has the least interest of $600

The other two investments (A and B) have the <u>same</u> amount of interest of $1800.

Step-by-step explanation:

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

<u>Investment A</u>

  • P = $2000
  • r = 10% = 0.1
  • t = 9 years

Substitute the given values into the formula and solve for I:

⇒ I = 2000(0.1)(9)

⇒ I = $1800

<u>Investment B</u>

  • P = $3000
  • r = 3% = 0.03
  • t = 20 years

Substitute the given values into the formula and solve for I:

⇒ I = 3000(0.03)(20)

⇒ I = $1800

<u>Investment C</u>

  • P = $2000
  • r = 10% = 0.1
  • t = 3 years

Substitute the given values into the formula and solve for I:

⇒ I = 2000(0.1)(3)

⇒ I = $600

The last investment (C) has the least interest of $600.

The other two investments (A and B) have the <u>same</u> amount of interest of $1800.

8 0
2 years ago
What is the answer?<br><br> [(12 − 5) • 12] ÷ 6
Sever21 [200]
(7 × 12 )/ 6
= 7×2
= 14
6 0
4 years ago
Read 2 more answers
Find (f-g)(x) when f(x)=3x+2 g(x)=2x^2-4 h(x)=x^2-x+7
Ad libitum [116K]
(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6
7 0
3 years ago
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