A manufacturer inspects 50 computer monitors and finds that 45 have no defects. What is the experimental probability that a moni
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Answer:
a) 6 1/4% of $3,875 is $242.18.
b) 16 2/3% of 96 lamps is 16 lamps.
c) 87 1/2% of 540.72 is 473.11
d) 33 1/3% of 750 boys is 252.52 boys
e) 66 1/2 % of 240 kg is 159.6 kg.
Step-by-step explanation:
x% of y is calculated as
Here calculating the given percentages:
a) 6 1/4% of $3,875
Now, 6 1/4 = 6+ 1/4 = 6.25
⇒6.25% of $3,875 =
Hence, 6 1/4% of $3,875 is $242.18.
b) 16 2/3% of 96 lamps
Now, 16 2/3 = 16+ 2/3 = 16.67
⇒16.67% of 96 lamps =
Hence, 16 2/3% of 96 lamps is 16 lamps.
c) 87 1/2% of 540.72
Now, 87 1/2 = 87+ 1/2 = 87.5
⇒87.5 % of 540.72 =
Hence, 87 1/2% of 540.72 is 473.11
d) 33 1/3% of 750 boys
Now, 33 1/3 = 33+ 1/3 = 33.67
⇒33.67 % of 750 boys =
Hence, 33 1/3% of 750 boys is 252.52 boys
e) 66 1/2 % of 240 kg
Now, 66 1/2 = 66+ 1/2 = 66.50
⇒66 1/2 % of 240 kg =
Hence, 66 1/2 % of 240 kg is 159.6 kg.