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2 years ago

111=13, 113=35, 115=57, 117=?

Mathematics

1 answer:

Elden [556K]2 years ago

3 0

In the pattern, the values are increasing by 22 each time so for the 117th term you take 57 + 22 = 79

So, 117= 79

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6 to the power of 2 equal ?

EleoNora [17]

Answer:

Step-by-step explanation:

Whenever something is to the power of 2, just think of the number multiplied twice :) Hoped this helped.

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2 years ago

Solve for x.

Ivanshal [37]

Answer:

x = -3.25

Step-by-step explanation:

2/5 = 0.4

0.4x - 0.2 = -2(3/4)

-2(3/4) = -2/1 * 3/4 = -6/4

0.4x - 0.2 = -6/4

Convert to fraction

2/5x - 1/5 = -6/4

Add 1/5 to both sides

-6/4 + 1/5 = -30/20 + 4/20 = -26/20

2/5x = -26/20

Convert to decimal

0.4x = -1.3

-1.3/0.4 = -3.25

x = -3.25

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2 years ago

Ms.Lawrence had 550 in her bank account. The next day she withdrew 120 to buy groceries. She deposited 200 two days later. Fout

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Answer:

541

Step-by-step explanation:

550-120+200-89=541

7 0

3 years ago

How many times do you multiply 5 by itself if the exponent is 56?

3241004551 [841]

56 times!!

This is because the exponent indicates how many times you multiply a number. For example:
5^2= 5x5

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2 years ago

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

3 years ago