All categories

4 years ago

A rectangle is 2/5 inches long and 1/3 inches wide what is the area of the rectangle

2 answers:

4 0

To find the area we do length times width. The easy thing with fractions is that you can just multiply across.

So 2/5 times 1/3.

2 x 1 = 2
5 x 3 =15

2/5 x 1/3 = 2/15.

Your answer is 2/15

~Deceptiøn

Agata [3.3K]4 years ago

3 0

2/5 x 1/3 = 2/15 square inches

You might be interested in

Will give brainliest if anyone helps me with this one.

alexandr402 [8]

Answer:

Step-by-step explanation:

i believe the answer is a

5 0

3 years ago

A football team plays in a large stadium. With a ticket price of $15, the average attendance at recent games has been 20,000. A

aleksley [76]

Answer:

R(x) = (20,000 - 400x)(15+x)

Step-by-step explanation:

Given,

The original price of each ticket = $ 15,

Original number of people or attendance = 20,000

Let the price of each ticket is increased by x times of $ 1,

That is, new price of each ticket = ( 15 + x ) dollars,

∵ for each $1 increase in the ticket price, attendance decreases by 400 people,

So, the new number of people = 20,000 - 400x

Since,

Revenue = number of people × price of each ticket

⇒ R(x) = (20,000 - 400x)(15+x)

Which is the required function.

4 0

3 years ago

What is the product of 7 and m? then evaluate the expression for m = 4.

ra1l [238]

the product of 7and m is 7m

if m=4

then the product is 7*4

=28

5 0

4 years ago

Read 2 more answers

rashid can paint 2 square feet of fence in 10 minutes how long will it take him to paint a fence 6 feet high by 25 feet long

Stells [14]

The area of the fence is 6*25=150 square feet.
It will take him 150 / 2 = 75 of 10-minute intervals. 75 min *10 = 750 min = 750/60 hours = 12.5 hours.

7 0

3 years ago

Read 2 more answers

How to find the general solution to y"'+2y"-4y'-8y=0?

S_A_V [24]

$y'''+2y''-4y'-8y=0$

has characteristic equation

$r^3+2r^2-4r-8=r^2(r+2)-4(r+2)=(r^2-4)(r+2)=(r-2)(r+2)^2=0$

which has roots at $r=\pm2$ . The negative root has multiplicity 2. So the general solution is

$y=C_1e^{2x}+C_2e^{-2x}+C_3xe^{-2x}$

8 0

3 years ago