How would I go about solving 12,15,18 thanks

Mathematics

1 answer:

grigory [225]3 years ago

3 0

For 12, you would do 90=4x+42, and 48=4x, and x=12
for 15, you would do 90=8x+66, and 24=8x, and x=3
for 18, you would do 90=3x+57, and 33=3x, and x=11

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Plsss help!! Write the equation of the line for the graph shown below.

anygoal [31]

Answer:

C. y = ½x + 4

Step-by-step explanation:

Equation for a line in slope-intercept form is given as y = mx + b

So, we need to find the slope (m) and the y-intercept (b) of the line given.

m = ∆y/∆x

Using two points on the line, (0, 4) and (-2, 3),

Slope (m) = (3 - 4)/(-2 - 0)

m = -1/-2

m = ½

y-intercept (b) = 4, this is where the line intercepts the y-axis.

To write the equation, substitute m = ½ and b = 4 into y = mx + b

Thus:

y = ½x + 4

3 0

2 years ago

Let X be a random variable with probability mass function P(X = 1) = 1 2 , P(X = 2) = 1 3 , P(X = 5) = 1 6 (a) Find a function g

Goryan [66]

The question is incomplete. The complete question is :

Let X be a random variable with probability mass function

P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6

(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.

(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)

Solution :

Given :

$P(X=1)=\frac{1}{2}, P(X=2)=\frac{1}{3}, P(X=5)=\frac{1}{6}$