Question

curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243, how mamy grams will remain after 12 days?

Answer 1

In this question, it is given that

Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243.

And we have to use the following formula, which is

$A(t) = A_{0} (1/2)^{t/h}$

Here t=12 days, half life, h =28.5 days . And the initial value ,A(0)=5.6 gms

So we will get

$A(t) = 5.6(1/2)^{12/28.5}$

$A(t) = 5.6* 0.747 =4.2 gm$

Therefore after 12 days, 4.2 gmsof curium-243 remains .

Answer 2

I think its going to be 4.18