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Pepsi [2]
3 years ago
10

Jett has to sell carnival tickets worth at least $50. The price of a child ticket is $4, and the price of an adult ticket is $6.

Let x be the number of child tickets sold and y be the number of adult tickets sold. Which of the following graphs best models this situation.
​
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer: 4x + 6y >/ 50

Step-by-step explanation:

The answer is A. 4x + 6y is greater than or equal to 50

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A $32 item is marked as 20% off. What is the sale price?
Natasha_Volkova [10]
$25.60

20%=.2
since it's 20% OFF, you want to get rid of .2 of the 32.
so 1-.2=.8
and .8 x 32 = 25.60
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Can you help me solve for x?
sergiy2304 [10]

Answer:

x = 12

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

10x-10 = 60 +4x+2

Combine like terms

10x-10 = 62+4x

Subtract 4x from each side

10x-4x -10 = 62 +4x-4x

6x -10 = 62

Add 10 to each side

6x-10+10 = 62+10

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3 years ago
What is the altitude of the equilateral triangle?
MAXImum [283]
It’s not going to be C because 10 is already in the question
7 0
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Find the surface area
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3 years ago
A sample of 10 adult elephants had an average weight of 12,556 pounds. The standard deviation
kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.25

The margin of error is:

M = T*s = 3.25*25 = 81

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

6 0
3 years ago
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