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3 years ago

Electricity cannot flow through the air. Is this true or false?

Chemistry

2 answers:

Marysya12 [62]3 years ago

8 0

Answer: TRUEEEEEEEEEEEEEEE

Explanation:

especially dry air

Mrrafil [7]3 years ago

4 0

it is not true my brotha/sista

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Solve the following problem and round the correct number of significant

RUDIKE [14]

Answer:

4.5 + 2.34 = 6.8

Sig Figs:

Decimals:

Scientific Notation:

6.8 × 10ⁿ

Words:

six point eight

5 0

3 years ago

A solution has a pH of 4.20. Using the relationship between pH and pOH, what is the concentration of OH−?

frez [133]

Answer : The concentration of $OH^-$ ion is, $1.58\times 10^{-10}M$

Solution : Given,

pH = 4.20

First we have to calculate the pOH.

As we know that,

$pH+pOH=14$

$pOH=14-pH$

$pOH=14-4.20$

$pOH=9.8$

Now we have to calculate the concentration of $OH^-$ ion.

$pOH=-\log [OH^-]$

$9.8=-\log [OH^-]$

$[OH^-]=1.58\times 10^{-10}M$

Therefore, the concentration of $OH^-$ ion is, $1.58\times 10^{-10}M$

4 0

3 years ago

Read 2 more answers

What do all akalis have in common

BaLLatris [955]

They all consist of Hydroxide particles (OH)
and they produce hydroxide ions (OH-) when placed in water/aqueous solution.

5 0

3 years ago

Nascar fans love race day when they get a chance to cheer on there favorite racer if a driver was able to travel 600 miles in 3

hjlf

Answer:

200 mph

Explanation:

600/3=200

5 0

3 years ago

A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?

sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

$ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g$

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

$PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)$

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0

4 years ago