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aliina [53]
3 years ago
8

Given the balanced equation representing a reaction: 4Al(s) 3O2(g) → 2Al2O3(s) As the aluminum loses 12 moles of electrons, the

oxygen (1) gains 4 moles of electrons (2) gains 12 moles of electrons (3) loses 4 moles of electrons (4) loses 12 moles of electrons
Chemistry
1 answer:
S_A_V [24]3 years ago
8 0
The answer is (2) gains 12 moles of electrons. In every chemical reaction, the electrons will not be destroyed or created, it will only transfer. So the Al loses electrons, the oxygen needs to gain the same amount of electrons.
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Answer A B C and D please for my chemistry hw
r-ruslan [8.4K]

<u>Answer:</u> The equations are provided below.

<u>Explanation:</u>

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

  • For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: H_2O(l)\rightarrow H_2(g)+O_2(g)

Balanced Equation: 2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

  • For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: HgO(s)\rightarrow Hg+O_2

Balanced Equation: 2HgO(s)\rightarrow 2Hg+O_2

  • For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Balanced Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

  • For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: Ca(OH)_2\rightarrow CaO+H_2O

Balanced Equation: Ca(OH)_2\rightarrow CaO+H_2O

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Which natural occurrence is shown ? Check all that apply.
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Answer:

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How do you rank the states of matter from highest to lowest in kinetic energy
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Plasma, Gas, Water, Solid
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Explanation:

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7 0
3 years ago
Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:
12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = <u>(-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}

∴  mass of S in 2 moles of S: w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g

<em>Given reaction</em>: 2S + 3O₂ → 2 SO₃

<em>In this reaction, the limiting reagent is S</em>

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ <u><em>The amount of heat produced by 42.8 g S:</em></u>

x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ

\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J

(\because 1 kJ = 10^{3} J)

<u>Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J</u>

8 0
3 years ago
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