The cell notation for the voltaic cell that incorporates the redox reaction Mg(s) + Sn²⁺(aq) → Mg²⁺(aq) + Sn(s) is Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s).
The cell notation for a voltaic cell is the following:
anode ║ cathode
The anode is where the oxidation reaction takes place and the cathode is where the reduction happens.
The given reaction is:
Mg(s) + Sn²⁺(aq) → Mg²⁺(aq) + Sn(s)
We can see that <u>magnesium </u>is <u>oxidizing</u> (it is losing electrons) and that <u>tin </u>is <u>reducing</u> (it is gaining electrons).
These two processes can be represented in the following half-reactions:
Oxidation: Mg(s) → Mg²⁺(aq)
Reduction: Sn²⁺(aq) → Sn(s)
Which in <u>cell notation</u> is:
Anode: Mg(s)|Mg²⁺(aq)
Cathode: Sn²⁺(aq)|Sn(s)
Hence, the <u>notation</u> for the <u>voltaic cell</u> is:
Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s)
Therefore, the cell notation for the voltaic cell with the given reaction is Mg(s)|Mg²⁺(aq)║Sn²⁺(aq)|Sn(s).
Learn more about voltaic cells here:
I hope it helps you!
Answer:
The period number tells which is the highest energy level occupied by the electrons.
Explanation:
- The period number (denoted by n) is the outer energy level that is occupied by electrons in an atom.
- The period number that an element is in, is the number of energy levels that the element has.
- When we move across a period from left to right in a periodic table the number of electrons in atoms increases within the same orbit.
Answer:
The answer to your question is V2 = 23.52 l
Explanation:
Data
Volume 1 = V1 = 22.5 l
Pressure 1 = P1 = 734 mmHg
Volume 2 = V2 = ?
Pressure 2 = 702 mmHg
Process
To solve this problem use Boyle's law.
P1V1 = P2V2
-Solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (734 x 22.5) / 702
-Simplification
V2 = 16515 / 702
-Result
V2 = 23.52 l
-Conclusion
If we diminish the pressure, the volume will be higher.