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dezoksy [38]
3 years ago
14

Your instructor has asked you to perform some research regarding a computer OS capability of distinguishing spoken words. What i

s the best search term to use for your research? (A) voice recognition(B) digital voice input(C) speech differentiation(D) speech identification
Computers and Technology
1 answer:
tekilochka [14]3 years ago
3 0
It’s A !!!!!!!!! Just did it
You might be interested in
Explain how the organ systems work together to warm up the body on a cold day
Tatiana [17]

Answer:

Your body is to cold ,blood vessels in the skin contract , and blood flow to the extremities (arms and legs)slows . muscles contract and relax rapidly which generates  heat to keep you warm..

Explanation:

Hope this helps :)

6 0
3 years ago
Read 2 more answers
Write a program second.cpp that takes in a sequence of integers, and prints the second largest number and the second smallest nu
sergey [27]

Answer:

The program is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

   int n;

   cout<<"Elements: ";

   cin>>n;

   vector <int>vectnum;

   int numInp;

   for (int i = 1; i <= n; i++){        cin>>numInp;        vectnum.push_back(numInp);    }

   int big, secbig;

   big = vectnum.at(0);      secbig = vectnum.at(1);

   if(vectnum.at(0)<vectnum.at(1)){     big = vectnum.at(1);  secbig = vectnum.at(0);   }

   for (int i = 2; i< n ; i ++) {

     if (vectnum.at(i) > big) {

        secbig = big;;

        big = vectnum.at(i);

     }

     else if (vectnum.at(i) > secbig && vectnum.at(i) != big) {

        secbig = vectnum.at(i);

     }

  }

  cout<<"Second Largest: "<<secbig<<endl;

  int small, secsmall;

  small = vectnum.at(1);       secsmall = vectnum.at(0);

  if(vectnum.at(0)<vectnum.at(1)){ small = vectnum.at(0);  secsmall = vectnum.at(1);   }

  for(int i=0; i<n; i++) {

     if(small>vectnum.at(i)) {  

        secsmall = small;

        small = vectnum.at(i);      }

     else if(vectnum.at(i) < secsmall){

        secsmall = vectnum.at(i);      }   }

  cout<<"Second Smallest: "<<secsmall;

  return 0;

}

Explanation:

See attachment for explanation

Download cpp
4 0
2 years ago
Have the javascript function CountingMinutes(str) take the str parameter being passed which will be two times (each properly for
jarptica [38.1K]

Using the knowledge in computational language in Java it is possible to write a code that function as CountingMinutes:

<h3>Writing the code in Java:</h3>

function CountingMinutes(str) {

     // code goes here  

     // Declare variables for calculating difference in minutes

     // variables in JavaScript are declared with "let" keyword

     /* Build regelar expression which will match the pattern of "12houttime-12hourtime"

        and extract time or hours in numbers from it */

     let extractedTimeStringArray = str.match(/(\d+)\:(\d+)(\w+)-(\d+)\:(\d+)(\w+)/);

     // extractedTimeStringArray array will be like- ["1:00pm-11:00am", "1", "00", "pm", "11", "00", "am", index: 0, input: "1:00pm-11:00am", groups: undefined]    for str = "1:00pm-11:00am"

     // console.log('object', time)

     

     // Extract array value at 1st index for getting first time's hours (ie time before hyphen like 1:00pm in 1:00pm-11:00am )  (like 11 from 11:32am) and convert them to minutes by multiplying by 60

     let mintsOfFirstTimeFromHours = extractedTimeStringArray[1] * 60;

     // Extract array value at 2nd index for getting first time's minutes like 32 from 11:32am

     let mintsOfFirstTimeFromMints = extractedTimeStringArray[2];

     // Extract array value at 4th index for getting second time's hours (ie time after hyphen like 11:00am in 1:00pm-11:00am ) and convert them to minutes by multiplying by 60

     let mintsOfSecondTimeFromHours = extractedTimeStringArray[4] * 60;

     // Extract array value at 5th index for getting second time's minutes like 32 from 11:32am

     let mintsOfSecondTimeFromMints = extractedTimeStringArray[5];

     // if second time's 12 hour time is in pm

     if (extractedTimeStringArray[6] === "pm") {

       // Add 12 * 60 = 720 minutes for 12 hrs

         mintsOfSecondTimeFromHours += 720;

     }

     // if first time's 12 hour time is in pm

     if (extractedTimeStringArray[3] === "pm") {

        // Add 12 * 60 = 720 minutes for 12 hrs to first time

       mintsOfFirstTimeFromHours += 720;

        // Add 12 * 60 *2 = 1440 minutes for 24 hrs to second time

       mintsOfSecondTimeFromHours += 1440;

     }

     // Calculate output minutes difference between two times separated by hyphen

    str = (mintsOfSecondTimeFromHours - mintsOfFirstTimeFromHours) + (mintsOfSecondTimeFromMints - mintsOfFirstTimeFromMints);

     // return calculated minutes difference

     return str;

   }

   // keep this function call here

   // call the function and console log the result

   console.log(CountingMinutes("1:00pm-11:00am"));

   // output in console will be-  1320

See more about Java at: brainly.com/question/12975450

#SPJ1

5 0
2 years ago
C programming question:
denpristay [2]

Answer:

You should do this:

if (0==strcmp(modelName,"Extravagant") && modelYear >= 1999 && modelYear <= 2002)

printf("%s\n","RECALL");

Explanation:

Lets consider this program and analyze the output.

int main()

{

int modelYear;

char modelName[30];

printf("enter the year");

scanf("%d",&modelYear);

printf("enter the modelname");

scanf("%s",modelName);

if (0==strcmp(modelName,"Extravagant") && modelYear >= 1999 && modelYear <= 2002)

printf("%s\n","RECALL");    }

if (0==strcmp(modelName,"Extravagant") && modelYear >= 1999 && modelYear <= 2002)

This statement has a function strcmp  which is used to compare two strings.

If the user enters Extravagant as model name then this input will be compared by the string stored in modelName i.e. Extravagant, character by character. If the string entered by the user matches the string stored in modelName this means this part of the if condition evaluates to true. 0==strcmp means that both the strings should be equal.

The next part of the if statement checks if the model year entered is greater than or equal to 1999 AND less than or equal to 2002. This means that the model year should be between 1999 and 2002 (inclusive).

&& is the logical operator between both the parts of if statement which means that both should evaluate to true in order to display RECALL.

This is correct way to use because the if (modelName == "Extravagant" && modelYear >= 1999 && modelYear <= 2002)  printf("%s\n","RECALL"); statement will not display RECALL. After entering the model name and model year it will move to the next line and exit.

So in if (0==strcmp(modelName,"Extravagant") && modelYear >= 1999 && modelYear <= 2002)

printf("%s\n","RECALL"); statement when the if condition evaluates to true, then RECALL is displayed in the output.

6 0
3 years ago
What might a programming prefer the top-down approach to programming design?
navik [9.2K]

Top down program design is an approach to program design that starts with the general concept and repeatedly breaks it down into its component parts. In other words, it starts with the abstract and continually subdivides it until it reaches the specific. Consider creating the prime factorization of a number like 1540. The steps involved might look like:

1540

2 x 770

2 x 2 x 385

2 x 2 x 5 x 77

2 x 2 x 5 x 7 x 11

Top down program design works the same way. We start with the overall objective and wind up with a series of steps needed to accomplish it.

3 0
3 years ago
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