Where is the list will all of this the list is needed
Answer:
<h2>d(4) = 64</h2>
Step-by-step explanation:
d(1) = 13
d(n) = d(n - 1) + 17
where
n is the nth term
To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term
So we have
<u>For the 2nd term</u>
That's d(2)
We have
d(2) = d(2-1) + 17
d(2) = d(1) + 17
But d(1) = 13
d(2) = 13 + 17 = 30
<u>For the 3rd term d(3)</u>
That's
d(3) = d(3 - 1) + 17
d(3) = d(2) + 17
d(3) = 30 + 17 = 47
<u>For the 4th term that's d(4)</u>
We have
d(4) = d(4 - 1) + 17
d(4) = d(3) + 17
d(4) = 47 + 17
We have the final answer as
<h3>d(4) = 64</h3>
Hope this helps you
The answer is C.) A+2/5B.
Adding equation A to 2/5B will result in canceling the x terms, i.e. 2/5x + 2/5(-x) = 0.
Answer:
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Step-by-step explanation:
Answer:
I'm sorry I can help you maybe a little bit if that's okay. Btw what grade are you in?
Step-by-step explanation:
