Answer:
yp = -x/8
Step-by-step explanation:
Given the differential equation: y′′−8y′=7x+1,
The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)
First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;
y′′−8y′=0
The auxiliary equation will give us;
m²-8m = 0
m(m-8) = 0
m = 0 and m-8 = 0
m1 = 0 and m2 = 8
Since the value of the roots are real and different, the complementary solution (yc) will give us
yc = Ae^m1x + Be^m2x
yc = Ae^0+Be^8x
yc = A+Be^8x
To get yp we will differentiate yc twice and substitute the answers into the original DE
yp = Ax+B (using the method of undetermined coefficients
y'p = A
y"p = 0
Substituting the differentials into the general DE to get the constants we have;
0-8A = 7x+1
Comparing coefficients
-8A = 1
A = -1/8
B = 0
yp = -1/8x+0
yp = -x/8 (particular integral)
y = yc+yp
y = A+Be^8x-x/8
Answer:
32 
Step-by-step explanation:
Given:
- The slant length 10 units
- A right square pyramid with base edges of length 8
Now we use Pythagoras to get the slant height in the middle of each triangle:
= 
= 
units
One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.
= 
= 6 units.
Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:
- The height 3 units
- A right square pyramid with base edges of length 4
So the volume of it is:
V = 1/3 *3* 4
= 32
Its 50. Because circumference is 314. Divide that by 3.14 and you get the diameter. Divide by another 2 and you get 50.
Answer:
80 as a product of prime numbers can be expressed as 2×2×2×2×5
