Answer:
Hey there!
These would also be acute angles.
Let me know if this helps :)
Answer:
Here's what I get
Step-by-step explanation:
a. Write an equation
(8x + 12y)² + (6x + 9y)²= (10x + 15y)²
b. Transform the equation
(i) Remove parentheses
64x² +192xy + 144y² + 36x² + 108xy + 81 y² = 100x² +300xy + 225y²
(ii) Combine like terms.
100 x² + 300xy + 225y² = 100x² +300xy + 225y²
The two sides are the same.
The equation is an identity.
Answer:
x=8.375
Step-by-step explanation:
Answer:
50 units
Step-by-step explanation:
Find the number of units x that produces the minimum average cost per unit C in the given equation.
C = 0.001x³ + 5x + 250
unit cost f(x) = C/x
= 0.001x³/x + 5x/x+ 250/x
f(x) = 0.001x² + 5 + 250/x
f'(x) = 0.002x - 250/x²
We equate the first derivative to zero
0.002x - 250/x² = 0
0.002x = 250/x²
Cross Multiply
0.002x × x² = 250
0.002x³ = 250
x³ = 250/0.002
x³ = 125000
x = 3√(125000)
x = 50 units
Therefore, the number of units x that produces the minimum average cost per unit C is 50 units.
Answer:
Step-by-step explanation:
Given data:
SS={0,1,2,3,4}
Let probability of moving to the right be = P
Then probability of moving to the left is =1-P
The transition probability matrix is:
![\left[\begin{array}{ccccc}1&P&0&0&0\\1-P&1&P&0&0\\0&1-P&1&P&0\\0&0&1-P&1&P\\0&0&0&1-P&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%26P%260%260%260%5C%5C1-P%261%26P%260%260%5C%5C0%261-P%261%26P%260%5C%5C0%260%261-P%261%26P%5C%5C0%260%260%261-P%261%5Cend%7Barray%7D%5Cright%5D)
Calculating the limiting probabilities:
π0=π0+Pπ1 eq(1)
π1=(1-P)π0+π1+Pπ2 eq(2)
π2=(1-P)π1+π2+Pπ3 eq(3)
π3=(1-P)π2+π3+Pπ4 eq(4)
π4=(1-P)π3+π4 eq(5)
π0+π1+π2+π3+π4=1
π0-π0-Pπ1=0
→π1 = 0
substituting value of π1 in eq(2)
(1-P)π0+Pπ2=0
from
π2=(1-P)π1+π2+Pπ3
we get
(1-P)π1+Pπ3 = 0
from
π3=(1-P)π2+π3+Pπ4
we get
(1-P)π2+Pπ4 =0
from π4=(1-P)π3+π4
→π3=0
substituting values of π1 and π3 in eq(3)
→π2=0
Now
π0+π1+π2+π3+π4=0
π0+π4=1
π0=0.5
π4=0.5
So limiting probabilities are {0.5,0,0,0,0.5}
