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White raven [17]
3 years ago
5

Annika was having fun playing poker. She needed the next two cards dealt to be diamonds so she could make a flush (five cards of

the same suit). There are 15 cards left in the deck, and five are diamonds. What is the probability that the two cards dealt to Annika (without replacement) will both be diamonds
Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer: 10%

Step-by-step explanation:

given data:

no of cards left = 15.

no of diamonds left = 5.

probability of drawing a diamond = 5/15.

probability that the next two cards drawn to anika are diamonds without replacements.

= 5/15 * 4/14

= 2/21

= 0.0952 * 100

the probability that the two cards dealt to Anika would be diamond is 9.52% ~ 10%

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If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
3 years ago
Suppose that a recent poll found that 49​% of adults believe that the overall state of moral values is poor. Complete parts​ (a)
Lunna [17]

Answer:

The mean of X is 122.5 and the standard deviation is 7.9.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they believe that the overall state of moral values is poor, or they do not believe this. The probability of an adult believing this is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

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In this problem, we have that:

n = 250, p = 0.49

So

E(X) = np = 250*0.49 = 122.5

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{250*0.49*0.51} = 7.9

The mean of X is 122.5 and the standard deviation is 7.9.

3 0
3 years ago
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