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White raven [17]
3 years ago
5

Annika was having fun playing poker. She needed the next two cards dealt to be diamonds so she could make a flush (five cards of

the same suit). There are 15 cards left in the deck, and five are diamonds. What is the probability that the two cards dealt to Annika (without replacement) will both be diamonds
Mathematics
1 answer:
salantis [7]3 years ago
6 0

Answer: 10%

Step-by-step explanation:

given data:

no of cards left = 15.

no of diamonds left = 5.

probability of drawing a diamond = 5/15.

probability that the next two cards drawn to anika are diamonds without replacements.

= 5/15 * 4/14

= 2/21

= 0.0952 * 100

the probability that the two cards dealt to Anika would be diamond is 9.52% ~ 10%

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Answer:

27 13/60

Step-by-step explanation:

What you have tried to do is not an impossible way to do it. What you could do is set your fractions and whole numbers like this.

( 7 + 1/10) * (3 + 5/6) I don't know if you know what FOIL is, but that is the way to proceed.

  • First: (meaning the first in each factor ).   3 * 7 =                                    21
  • Outside: (meaning the two terms near outside the brackets) 7 * 5/6 = 5 5/6
  • Inside: The two terms closest to the * sign      1 / 10  *3 =                         3/10
  • Last: The two end terms    (1/10 * 5/6 = 5/60                                              5/60

Now you can add. 21 + 5 is the whole number amount = 26

Add the fractions

  • 5/6 + 3/10 + 5/60 The lowest common multiple is 60
  • 50/60 + 18/60 +5/60 = 73 / 60 = 1 and 13/60

Add that to 26 and you get 27 13/60

3 0
3 years ago
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Answer:

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