All categories

3 years ago

A pre-algebra book is 8 space 1 half inches by 9 space 1 fourth inches. Determine the perimeter of the textbook

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

8 0

Rectangular book

two 8 1/2 sides

two 9 1/4 sides

8 1/2*2=17

9 1/4*2=18 1/2

17+18 1/2= 35 1/2

The perimeter of the textbook is 35 1/2 inches or 35.5 inches.

Hope this helps :)

You might be interested in

A six sided fair die is rolled with two coins, all sides of a fair die have equal chances of being displayed ,Find the probabili

Marta_Voda [28]

6% is the correct answer

7 0

1 year ago

Find the surface area of the rectangular prism. 8 yd 4 yd 5 yd Answer: yd? Submit Answer

Rashid [163]

The area of the circle is 18

3 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

here is the base of a prism if the height of the prism is 5cm what is it’s surface area? what is it’s volume

denpristay [2]

<h2>Volume Of Prism</h2>

Here is the base of a prism if the height of the prism is 5cm what is it’s surface area? what is it’s volume.

<h3>Solution:</h3>

Volume = s²
V = 5cm
V = 5cm x 5cm
V = 25cm²

- So The Surface area of Prism is 25cm².

#ProblemSolve

3 0

2 years ago

Read 2 more answers

The company sold four more than three times as many cars this month compared to last month. If 37 were sold this month, how many

belka [17]

11 were sold last month

4 0

3 years ago