Question

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Answer 1

Answer:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

Step-by-step explanation:

Using:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

x^2-3x+1=0

So, a=1   b=-3  c=1

$x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}$

We have two solutions:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$