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alexandr1967 [171]
3 years ago
12

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Mathematics
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

Step-by-step explanation:

Using:

x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}

we will have two solutions.

x^2-3x+1=0

So, a=1   b=-3  c=1

x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}

We have two solutions:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

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